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evablogger [386]
3 years ago
12

Help plssssssssbssssssss

Mathematics
1 answer:
borishaifa [10]3 years ago
8 0

Answer:

i think its C or B im not really positive, sorry :(

Step-by-step explanation:

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What is the measure of
Nata [24]

Answer:

9

Step-by-step explanation:

3x+18+9x-27=99

12x-9=99

12x=108

x=9

7 0
3 years ago
How do I solve? What do I do?
KonstantinChe [14]
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An odd multiple of 6 which is less than 100
Kipish [7]

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3 years ago
Algebra 2!exponential growth rate of 7%?
bixtya [17]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Suppose ancient Romans had a 0.2 chance of dying in each of the following age intervals: [0, 2], [2, 10], [10, 30], [30, 70] and
Pani-rosa [81]
<span>65 As for the reason the average life expectancy of a Roman who reaches the age of 30 being so much higher than the average expectancy overall, that's simply a matter of taking the average of 50 and 80, verses the average of 1,6,20,50,80. Let's illustrate that by calculating the average life expectancy of a Roman at birth, and after age 30. For birth, there's 5 ranges, each of which has the same probability. They are [0,2]: Midpoint = 1. Probability = 0.2. Product = 1*0.2 = 0.2 [2,10]: Midpoint = 6. Probability = 0.2. Product = 6*0.2 = 1.2 [10,30]: Midpoint = 20. Probability = 0.2. Product = 20*0.2 = 4 [30,70]: Midpoint = 50. Probability = 0.2. Product = 50*0.2 = 10 [70,90]: Midpoint = 80. Probability = 0.2. Product = 80*0.2 = 16 Sum = 0.2 + 1.2 + 4 + 10 + 16 = 31.4 But upon reaching 30, there is no longer a mere 0.2 probability for those last 2 slots. The chart looks like [30,70]: Midpoint = 50. Probability = 0.5. Product = 50*0.5 = 25 [70,90]: Midpoint = 80. Probability = 0.5. Product = 80*0.5 = 40 Sum = 65 If you look at each possible range of ages, the actual life expectancy is at birth: 31.4 years after age 2: 39 years after age 10: 50 years after age 30: 65 years after age 70: 80 years</span>
7 0
4 years ago
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