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3 years ago

Scatter plots and Line of Best Fit

Mathematics

1 answer:

m_a_m_a [10]3 years ago

6 0

The answer will be 60+ because 48 minutes is a long time and if youstudy for a long time you memorize more

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Help please!!

Semenov [28]

D. No because two points with the same x value have different y values. A function cannot have one x equal different y

4 0

2 years ago

While shopping at Walmart, I had the option to buy either a 12 pack of Soda for $13, or I could buy a 24 pack for $24. Based on

ira [324]

Answer:

The 24 pack for 24 dollars!

Step-by-step explanation:

This is because you see that 12 is 1/2 of 24 and if you do 13x2 you get 26$ so for the 12 pack if you double it you will be paying 2$ more than if you got the OG 24 pack

8 0

2 years ago

Read 2 more answers

Factor 27 + d^ 3completely.

Sedaia [141]

Answer:

(3+d)(9-3d+d^2)

Step-by-step explanation:

a^3 + b^3 = (a+b)(a^2-ab+b^2)

a= 3

b= d

7 0

2 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

2 years ago

What is 10 to the power of 7?

Sophie [7]

100000000 needed to take up space to give you answr

5 0

3 years ago

Read 2 more answers