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Elza [17]
3 years ago
10

Write an equation of the line that passes through (-1,3) and is parallel to the line y = 2x + 2.

Mathematics
1 answer:
Jlenok [28]3 years ago
5 0

Answer:y=2x+3

Step-by-step explanation: the slope will be the same as the slope for the other equation since its parallel to it. then you plug in the point to the equation so 3 would be y and x would be -1. then you solve that equation and get the answer for the y intercept which goes on the end of the equation.

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Round 34,571 to the place value of the underlined digit. underlined digit is 5
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Read 2 more answers
Question:
Setler79 [48]
To find equivalent equations, you simply have to simplify both of these :)

a)  5/6(x - 6) + 1/6(3 - x)

Simplify.

5/6x - 5 + 1/2 - 1/6x

Add like terms.

(5/6x - 1/6x) + (-5 + 1/2)

Simplify.

4/6x +(-4.5)

Simplify.

2/3x - 4.5

b) (y + 7)4 + 8 - 5y

Simplify.

4y + 28 + 8 - 5y

Add like terms.

(4y - 5y) + (28 + 8)

Simplify.

-y + 36

~Hope I helped!~
4 0
3 years ago
a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F
slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

               M= (c^2)/8 which is intern equal to 2\sqrt{2}

Step-by-step explanation:

           Find the area, by setting the limits as

               = 4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}4d\theta

                 =8\pi

Therefore;

Mxy=  \int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta

       z-bar = 8/3

M= 8\pi dividing it into two volume gives us = 4\pi

means  4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta

             4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)

              c=2\sqrt{2}

       

                 

                 

5 0
3 years ago
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