Answer:
The length of side AC is 5 units.
The areas of triangle ABC is 10 square units.
Step-by-step explanation:
From point A (1,3) to point C (1,-2) is 5 units
To check this:
3 - (-2) = 3 + 2 =5
We're subtracting since the point went down (from positive 3 to negative 2)
Now for the area:
Area formula for a triangle: 
bh = ⋅b⋅h
We already found the height (length) : 5
The base is from point C (1,-2) to point B (5,-2), which is 4 units
To check this:
5 - 1 = 4
Now that we have found the base and height, Let's solve:
⋅4⋅5 = ⋅20 = 10
Our area is 10 square units.
Hope that helps :)
Answer:
37.5 hrs
Step-by-step explanation:
You do cross multiplication hours on top and weeks on the bottom.
Answer:
And we can find the individual probabilities using the probability mass function
And replacing we got:
Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Solution to the problem
Let X the random variable of interest "number of automobiles with both headligths working", on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
And for this case we want to find this probability:
And we can find the individual probabilities using the probability mass function
And replacing we got:
Please refer to the above attachment
Answer:
or
Step-by-step explanation:
The expression 
can be simplified by first writing the fraction under one single radical instead of two.
5/15 simplifies because both share the same factor 5.
It becomes 
This can simplify further by breaking apart the radical.
A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.
