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77julia77 [94]
4 years ago
8

A fellow calculus enthusiast was working through some practice problems.

Mathematics
2 answers:
Mazyrski [523]4 years ago
4 0

\dfrac{3x^2+1}{2x}=\dfrac{3x}2+\dfrac1{2x}

Integrating this gives

\dfrac{3x^2}4+\dfrac12\ln|x|+C

so the enthusiast's antiderivative is incorrect.

Without integrating, you can show the enthusiast's solution is incorrect by taking the derivative:

\dfrac{\mathrm d}{\mathrm dx}\left(\dfrac{x^3+x}{x^2}+C\right)=\dfrac{\mathrm d}{\mathrm dx}\left(x+\dfrac1x\right)=1-\dfrac1{x^2}=\dfrac{x^2-1}{x^2}

but this is not the same as the original integrand.

Viktor [21]4 years ago
4 0

Answer:

the enthusiast's antiderivative is incorrect

Step-by-step explanation:

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