Answer:
16.28 mph ; 79.38°
Step-by-step explanation:
Given the following :
Speed of child due east = 3mph
Speed of ship due North = 16mph
Relative speed of th child is obtained by using Pythagoras rule to find the hypotenus
Relative Speed = Sqrt(3² + 16²)
Relative Speed = sqrt(9 + 256)
= sqrt(265)
= 16.2788 mph
= 16.28 mph
From trigonometry ;
Tanθ = opposite / Adjacent
Tanθ = (16 / 3)
Tanθ = 5.333
θ = tan^-1(5.333)
θ = 79.379°
θ = 79.38°
Answer:

Step-by-step explanation:
Since Quadrilateral ABCD ~ PQRS, therefore:

Let's find the value of x by using the ratio of two corresponding sides of both quadrilaterals. Let's use:

CD = 5
RS = 4.5
DA = 4
SP = x

Cross multiply


Divide both sides by 5


To find the Chebyshev's inequality, P | Xn - E(X)| <= δ/4 >= 1 - (δ^2/25)/(δ^2/16) = 1 - (16/25) = 9/25 = 0.36
The answer in this question which is the probability that the average of the physicist's measurement is within δ/4 units of the actual specific gravity is at least 0.36%
I hope you find the answer I needed points quickly I’m doing a timed quiz I apologize