HELP!! URGENT!! 75 POINTS + BRAINLIEST!!

Mathematics

1 answer:

Anna71 [15]3 years ago

3 0

The picture is grey I can’t see it

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What is the independent variable of an equation?

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The independent variable of an equation is x, or something u can change. in linear equations, for example, it is y=3x+4. and x is the independent variable cause most of the time u will plug in or substitute a number for x.

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!!WILL MARK BRAINLIEST!!

iren2701 [21]

Answer:

4) 8

Step-by-step explanation:

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sonja wants to have $14000 in 13 years. calculate how much she should invest now at 6% interest, compounded semiannually in orde

mariarad [96]

She should invest $6491.73.

The equation we use to solve this is in the form
$A=p(1+\frac{r}{n})^{nt}$ ,
where A is the total amount in the account, p is the principal invested, r is the interest rate as a decimal, n is the number of times per year the interest is compounded, and t is the amount of time.

A in our problem is 14000.
p is unknown.
r is 6% = 6/100 = 0.06.
n is 2, since it is compounded semiannually.
t is 13.

$14000=p(1+\frac{0.06}{2})^{13*2}
\\
\\14000=p(1+0.03)^{26}
\\
\\14000=p(1.03)^{26}
\\
\\\text{Dividing both sides by }1.03^{26}\text{, we have}
\\
\\\frac{14000}{1.03^{26}}=\frac{p(1.03)^{26}}{1.03^{26}}
\\
\\6491.73\approx p$

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2 years ago

Help with finding proofs

nadya68 [22]

Answer:

Statement: ∠XYZ = ∠ABC Reasons: Below

Step-by-step explanation:

For two angles to be complementary means that the sum of the two angles is equivalent to 90°. When an angle has one of those little squares, that means the angle is a right angle, or a 90° angle. Also, since it's given that line segment AB and line segment BC are perpendicular, this means the two lines/line segments cross each other at a right angle, which also proves that line segment AB and BC have a 90° angle.

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10 months ago

A third-degree polynomial function f has real zeros -2, ½, and 3, and its leading coefficient negative. Write an equation for f.

WARRIOR [948]

Hello,

y=-k(x+2)(x-1/2)(x-3) where k is a real positive.

We may chose k=1
There are an infinite solutions.

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