PLEASE HELP ME ASAP!!! i need help!!!
2 answers:
Answer:
fourth option
Step-by-step explanation:
Using the sine and cosine ratios in the right triangle and exact values
sin60° = , cos60° =
, then
sin60° = =
=
( cross- multiply )
2x = 4 ( divide both sides by 2 )
x = 2
---------------------------------------------------------
cos60° = =
=
( cross- multiply )
2y = 4 ( divide both sides by 2 )
y = 2
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Answer:
B) (−1, 3)
Step-by-step explanation:
The standard form of a quadratic function is
y = ax² + bx + c
The vertex form of a parabola is
y = a(x - h)² + k
where (h, k) is the vertex of the parabola.
h = -b/(2a) and k = f(h)
In your equation, ƒ(x) = −3x² − 6x
a = -3; b = -6; c = 0
Calculate h
h = -(-6)/2(-3)]
h = 6/(-6)
h = -1
Calculate k
k = -3(-1)² -6(-1)
k = -3 + 6
k = 3
So, h = -1, k = 3, a = -3
The vertex form of the equation is f(x) = -3(x + 1)² + 3.
The vertex is at (-1, 3).
The figure below shows the graph of ƒ(x) = −3x² − 6x with the vertex
at (-1, 3).
