The square root of pi is 1.77245385091.
Answer:
3.00x10^8
Step-by-step explanation:
So you want to make sure the number before the x10^ is beween 10 and 0 not including 10 and 0. So 1.00-9.99.
Move the demcil place up in 300,000,000 till your first number is between 1 and 9.99.
Then count how many places you moved it up, in this case 8
Add the amount of times you moved up to the x10^(in this space).
you answer is now 3.00 plus the x10^8
3.00x10^8
The given equation is of the form y = m x + b where m is the slope and b is the y intercept that is value of y when x =0 , or we can say b is the initial value.
In the given equation which is y = 4t+2, on comparing we will get m =4 that is slope is 4 and here slope represents the rate or speed and 2 is the y intercept that is b. And 2 represents the initial position that is, the ant is 2 units from the home initially .
E) 2
Remember that the first derivative of a function is the slope of the function at any specified point. We've been told that f(0) = -5 and that f'(x) is always less than or equal to 3. So let's look at the available options and see what the average slope would have to be in order to get the specified value of f(2).
A) -10: (-10 - -5)/(2 - 0) = -5/2 = -2.5
B) -5: (-5 - -5)/(2 - 0) = 0/2 = 0
C) 0: (0 - -5)/(2 - 0) = 5/2 = 2.5
D) 1: (1 - -5)/(2 - 0) = 6/2 = 3
E) 2: (2 - -5)/(2 - 0) = 7/2 = 3.5
Now taking into consideration the mean value theorem, the value of the function f'(x) has to have the value equal to the average slope between the two points at at least one point between the two given values. For options A, B, C, and D it's possible for f'(x) to return values that make that slope possible. However, for option E, the mean value theorem indicates that f'(x) has to have the value of 3.5 for at least 1 point between x=0 and x=2. And since we've been told that f'(x) is less than or equal to 3 for all possible values of x, that is in conflict and f(2) can not have the value of 2.
You just have to use the squares one to factor this and this is what I got.
