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mafiozo [28]
3 years ago
10

Find the vertex for the parabola given by the function ƒ(x) = −3x^2 − 6x.

Mathematics
1 answer:
telo118 [61]3 years ago
4 0

Answer:

B) (−1, 3)  

Step-by-step explanation:

The standard form of a quadratic function is  

y = ax² + bx + c

The vertex form of a parabola is

y = a(x - h)² + k

where (h, k) is the vertex of the parabola.

h = -b/(2a) and k = f(h)

In your equation, ƒ(x) = −3x² − 6x

a = -3; b = -6; c = 0

Calculate h

h = -(-6)/2(-3)]

h = 6/(-6)

h = -1

Calculate k

k = -3(-1)² -6(-1)

k = -3 + 6

k = 3

So, h = -1, k = 3, a = -3

The vertex form of the equation is  f(x) = -3(x + 1)² + 3.

The vertex is at (-1, 3).

The figure below shows the graph of ƒ(x) = −3x² − 6x  with the vertex

at (-1, 3).

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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We have been given that the diameter of a smaller circle is 7 km and the width of the circular path is 0.5 km. We are asked to find the area of the path.

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We know that radius is half the diameter, so radius of smaller circle would be \frac{7}{2}=3.5 km.

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