Answer:
The value of pressure at an altitude of 10000 ft = 10 
Step-by-step explanation:
Given data
Atmospheric pressure
= 14.7 
Pressure at 4000 ft = 12.6 
If temperature is constant then the atmospheric pressure is varies with the altitude according to law
P (h) =
------ (1)
where k= constant & h = height
12.6 = 14.7 
0.857 = 
㏑ 0.857 = - 4000 k
-0.154 = - 4000 k
k = 3.85 × 
Thus the atmospheric pressure at an altitude of 10,000 ft is
14.7 ×
----- (2)
Product of k & h is
k h = 3.85 ×
× 10000
k h = 0.385
Put his value of k h = 0.385 in equation (2) we get
14.7 × 
10 
This is the value of pressure at an altitude of 10000 ft.
let's firstly convert the mixed fraction to improper fraction and then multiply.
![\bf \stackrel{mixed}{3\frac{2}{5}}\implies \cfrac{3\cdot 5+2}{5}\implies \stackrel{improper}{\cfrac{17}{5}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{17}{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\implies 17](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B2%7D%7B5%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%205%2B2%7D%7B5%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B17%7D%7B5%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B17%7D%7B~~%5Cbegin%7Bmatrix%7D%205%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%5Ccdot%20~~%5Cbegin%7Bmatrix%7D%205%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%5Cimplies%2017)
Answer:
Klorina's rate in still water is 4.5 km/h
Current's rate is 0.5 km/h
Step-by-step explanation:
Let
x km/h = Klorina's rate in still water
y km/h = current's rate
<u>With the current (current helps):</u>
Distance = 10 km
Time = 2 hours
Rate = x + y km/h

<u>Against the current:</u>
Distance = 8 km
Time = 2 hours
Rate = x - y km/h

Divide both equations by 2:

Add these equations:

Subtract these two equations:

Answer:
2×2×5×5
Step-by-step explanation:
1st of all they are prime factors
if multiplied give us 100