Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
Answer:
3 would be your y intercept
then from the point 0,0 put 2 in as slope
Step-by-step explanation:
First turn the equation into y=mx+b (slope-intercept form)
Which turns into y= -2x+3
in y=mx+b
m is slope and b is y intercept
3 would be your y intercept
then from the point 0,0 put 2 in as slope
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Answer:
Step-by-step explanation:
61 is divisible by itself and 1. It's prime.
102 ends in a 2. Therefore it is not prime because it can be divided by 2,
75 = 3*5*5 not prime.
64 = 2 * 2 * 2 *2 * 2*2 Not prime.
Answer:
Step-by-step explanation:
7x + 3= 24
7x= 24-3
7x= 21
x= 21/7
x= 3
Then we have that
5-4x
5-4(3)
5-12
Answer= -7
