Answer:
7x + 2y = 1
Step-by-step explanation:
1. Find the slope of the line.
(y2-y1)/(x2-x1) ----> (11 - (-3))/((-3) -1) ----> (11+3)/ (-3 -1) ----> 14/-4
*lets simplify into (7/-2)*
2. Write into slope intercept form.
y=mx+b (m is the slope) (b is the y intercept)
y = (7/-2)x + b
We now need to find the value of b, this can be done by plugging in values of x and y, and using algebra to solve.
11 = (7/-2)(-3) + b
11 = 10.5 + b
b = 0.5 or 1/2
slope intercept form y = (7/-2)x + 1/2
Now we convert to standard form: ax+by=c
*In this form we our a term cannot be a fraction nor can it be negative*
1. Get x and y on the same side, and since our x term is negative right now, we can make it positive by adding it on both sides.
(7/2)x + y = 1/2
2. We now want to get rid of the fraction in term a, so we multiply the entire function by two, so the denominator cancels out.
2(7/2)x + 2y = 2(1/2)
Simplify and you get
7x + 2y = 1
we have <D = (7x-1)° , <A =(5x+25)°
{ all angles of square is equal to 90° }
<A + <D = 180°
5x + 25 + 7x - 1 = 180°
12 x = 180 - 24
12x = 156
x = 13
<A = (5*13 +25) = 90
< D = ( 7*13-1) = 90
so ABCD is a square
Answer:
y= - 3/2x + 7 hope this helps you out :)
