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nikdorinn [45]
3 years ago
5

2r=5s/2-s/4 solve for s

Mathematics
2 answers:
makkiz [27]3 years ago
4 0
Multiply the whole equation by 4 to cancel out the fractions.
<span>(2r = 5s/2 - s/4)*4
8r = 10s - s
8r = 9s
8r/9 = s
s = 8r/9</span>
nikitadnepr [17]3 years ago
4 0

Answer:

s=\frac{8r}{9}

Step-by-step explanation:

The given equation is

2r=\frac{5s}{2}-\frac{s}{4}

We need to solve this equation for s.

Simplify the right side of the equation.

Taking LCD on right side of the equation we get

2r=\frac{2(5s)-s}{4}

2r=\frac{10s-s}{4}

2r=\frac{9s}{4}

Multiply both sides by 4.

2r\times 4=\frac{9s}{4}\times 4

8r=9s

Divide both sides by 9.

\frac{8r}{9}=s

Interchange the sides.

s=\frac{8r}{9}

Therefore, the value of s is s=\frac{8r}{9}.

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The area of a circle is 2464cm2.calculate it's diameter to 2 significant figures<br>​
tigry1 [53]

Answer:

hi

Step-by-step explanation:

Answer:

The diameter of the circle is 56 cm.          

Step-by-step explanation:

Given : The area of the circle is 2464 cm square.

To find : The diameter of the circle?

Solution :

The area of the circle is defined as

Where, A=2464 cm² is the area,

r is the radius

Substituting the values,

Radius of the circle is 28 cm.

The diameter of the circle is  

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2 years ago
Can someone please help me on this question <br> I will give brainliest
xz_007 [3.2K]

Answer:

A) 3 in

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Geometry</u>

  • Surface Area of a Sphere: SA = 4πr²
  • Diameter: d = 2r

Step-by-step explanation:

<u>Step 1: Define</u>

SA = 23 in²

<u>Step 2: Find </u><em><u>r</u></em>

  1. Substitute [SAS]:                    23 in² = 4πr²
  2. Isolate <em>r </em>term:                         23 in²/(4π) = r²
  3. Isolate <em>r</em>:                                  √[23 in²/(4π)] = r
  4. Rewrite:                                   r = √[23 in²/(4π)]
  5. Evaluate:                                 r = 1.35288 in

<u>Step 3: Find </u><em><u>d</u></em>

  1. Substitute [D]:                    d = 2(1.35288 in)
  2. Multiply:                              d = 2.70576 in
  3. Round:                                d ≈ 3 in
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Likurg_2 [28]

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