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SVEN [57.7K]
3 years ago
8

Pls help someone need turn in

Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

Answer:

the answer is the third option on the top row

Step-by-step explanation:

hope this helps!

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2sin^2 2x=2<br><br> In the domain [0,2pi)<br><br> What can x equal ( in radians).
lions [1.4K]
Bear in mind that, when it comes to trigonometric functions, the location of the exponent can be a bit misleading, however recall that sin²(θ) is really [ sin( θ )]²,


\bf 2sin^2(2x)=2\implies sin^2(2x)=\cfrac{2}{2}&#10;\\\\\\&#10;sin^2(2x)=1\implies [sin(2x)]^2=1\implies sin(2x)=\pm\sqrt{1}&#10;\\\\\\&#10;sin(2x)=\pm 1\implies sin^{-1}[sin(2x)]=sin^{-1}(\pm 1)

\bf \measuredangle 2x=sin^{-1}(\pm 1)\implies \measuredangle 2x=&#10;\begin{cases}&#10;\frac{\pi }{2}\\\\&#10;\frac{3\pi }{2}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\measuredangle 2x=\cfrac{\pi }{2}\implies \measuredangle x=\cfrac{\pi }{4}\qquad \qquad \qquad \qquad \measuredangle 2x=\cfrac{3\pi }{2}\implies \measuredangle x=\cfrac{3\pi }{4}
3 0
3 years ago
Point Q' is the image of Q (4,-6) is under a translation by 1 unit to the right.
alexandr1967 [171]

Answer:

The coordinates of point Q' would be (5, -6) after being translated 1 unit to the right.

Step-by-step explanation:

4 0
3 years ago
A couple quick algebra 1 questions for 50 points!
kkurt [141]

Answer:

Question 6) Neither (Not an inverse variation)

Question 7) Inverse variation

Question 8) Inverse variation

Step-by-step explanation:

These are the two formulas we need to know prior to solving the question.

Direct variation: c times x

Inverse variation: c times 1/x --> c/x

- Here, c is the constant

6. y = x + 7

This is neither. It is not in the form of a direct, or inverse variation, so it does not belong in any category.

7. 14 = xy

This equation is an inverse variation.

xy = 14

y = 14/x

14 is the constant, and the format is the same as for an inverse variation.

8. x = -8/y

This equation is an inverse variation.

yx = -8

y = -8/x

-8 is the constant, and the format is the same as for an inverse variation.

So we can conclude that questions 7 and 8 is an inverse variations, while question 6 isn't.

6 0
2 years ago
Read 2 more answers
Write an equation in the form y = mx for the relationship shown in the graph below.​
faltersainse [42]
The Answer Is: y= 2x
5 0
2 years ago
Read 2 more answers
Help mee pleaseee :(
fgiga [73]

Answer:

y = - 2x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (1, - 1) and (x₂, y₂ ) = (2, - 3) ← 2 ordered pairs from the table

m = \frac{-3-(-1)}{2-1} = \frac{-3+1}{1} = - 2 , then

y = - 2x + c ← is the partial equation

To find c substitute any ordered pair from the table into the partial equation

Using (3, - 5 ) , then

- 5 = - 6 + c ⇒ c = - 5 + 6 = 1

y = - 2x + 1 ← equation of line

3 0
3 years ago
Read 2 more answers
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