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2 years ago

Pls help someone need turn in

Mathematics

1 answer:

Alinara [238K]2 years ago

6 0

Answer:

the answer is the third option on the top row

Step-by-step explanation:

hope this helps!

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Work out m and c for the line:<br> y−4x=−1

Eduardwww [97]

Step-by-step explanation:

y -4x = -1

y = 4x -1

then y = Mx + b

m = 4

b = -1

7 0

3 years ago

What is the midpoint of the segment shown below?

Burka [1]

Answer:

choice. c.) (5, 1/2)

Step-by-step explanation:

(5, 4) and (5, -3)

Use midpoint formula ( (a + x)/2 , (b + y)/2) for (a,b), (x,y)

midpoint = ( (5+5)/2, (4+- 3)/2) = (5, 1/2)

5 0

3 years ago

Answer correct you get brainliest answer

zloy xaker [14]

Answer:

$y = {x}^{2} - 2$

Or if you want with the value of h too.

$y = {(x - 0)}^{2} - 2$

Step-by-step explanation:

$y = a {(x - h)}^{2} + k$

Find the value of h and k by using the formula.

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

From y = x²-2

$a = 1 \\ b = 0 \\ c = - 2$

Substitute these values in the formula.

$h = - \frac{0}{2(1)} \\ h = 0$

Therefore, h = 0.

$k = \frac{4(1)( - 2) - {0}^{2} }{4(1)} \\ k = \frac{ - 8}{4} \\ k = - 2$

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

$y = a {(x - h)}^{2} + k \\ y = 1 {(x - 0)}^{2} - 2 \\ y = {(x)}^{2} - 2 \\ y = {x}^{2} - 2$

These type of equation where b = 0 can also be both standard and vertex form.

4 0

3 years ago

What is the range of the function f(x)=6x+5 for the domain {-1,0,1,2,3}

bogdanovich [222]

{-1, 5, 11, 17, 23} ................

6 0

2 years ago

Find the slope of the line that contains these two points.<br> (2, -5) and (7, -10)

Paul [167]

M= $\frac{y1-y2}{x1-x2}$ = $\frac{-5-(-10)}{2-7}$ = $\frac{5}{-5} =-1$
Answer: slope is -1

4 0

3 years ago

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