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rewona [7]
2 years ago
8

3. How many 3 digit all even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?

Mathematics
2 answers:
Colt1911 [192]2 years ago
7 0
<h2>Answer:</h2>

36

<h3>Step-by-step explanation:</h3>

Solution:

6\times6=36

such\ as:

11\ \ \ 22\ \ \ 33\ \ \ 44\ \ \ 55\ \ \ 66\\ 12\ \ \ 21\ \ \ 31\ \ \ 41\ \ \ 51\ \ \ 61\\ 13\ \ \ 23\ \ \ 32\ \ \ 42\ \ \ 52\ \ \ 62\\ 14\ \ \ 24\ \ \ 34\ \ \ 43\ \ \ 53\ \ \ 63\\ 15\ \ \ 25\ \ \ 35\ \ \ 45\ \ \ 54\ \ \ 64\\ 16+263646+56\\ 6+6+6+6+6+6\\ =36.

<em>I hope this helps you</em>

<em>:)</em>

Ludmilka [50]2 years ago
4 0

Step-by-step explanation:

Only 3 numbers are possible at units place (2, 4 & 6) as we need even number.

But at tens & hundreds place all 6 are possible

<u>Number of 3 digit even numbers</u>

= 3x6x6 = 108

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Annually The amount after 10 years = $ 7247.295

quarterly compound after 10 years = $7393.5

Continuously interest =$7,419

Given:

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t = time in years

n = number of times the amount is compounding.

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The principal amount is, P = $4500

The rate of interest is, r = 5% =5/100 = 0.05.

The time in years is, t = 10.

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Answer: The amount after 10 years = $4500+$2,919=$7,419

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