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Rzqust [24]
3 years ago
7

Find the quotient of 2/7 and 3/5

Mathematics
2 answers:
charle [14.2K]3 years ago
6 0
The quotient of 2/7 is 2 ÷ 7 = 0.285714
And 3/5 is 3 ÷ 5 = 0.6
IrinaK [193]3 years ago
4 0

Answer:

\frac{10}{21}

Step-by-step explanation:

<u>Operations With Fractions</u>

Evaluate the expression:

\displaystyle m=\frac{\frac{2}{7}}{\frac{3}{5}}

The division of fractions is usually done by multiplying the fraction on the numerator by the reciprocal of the fraction on the denominator:

\displaystyle m=\frac{\frac{2}{7}}{\frac{3}{5}}=\frac{2}{7}\cdot\frac{5}{3}

Operating:

\displaystyle m=\frac{\frac{2}{7}}{\frac{3}{5}}=\frac{10}{21}

This fraction cannot be reduced.

Answer: \frac{10}{21}

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exercise 1.3. a telephone number consists of ten digits, of which the first digit is one of 1;2;:::;9 and the others can be 0;1;
dezoksy [38]

Answer:

The probability that "0" appears at most once in a telephone number is 0.82

Step-by-step explanation:

Telephone number = 10 digits

First digit = (1,2......9)------> there are 9 possible digits

digit 2 - digit 10 = (0,1,2......9) -----> there are 10 possible digits

Let's find the total amount of telefone numbers with those characteristics:

possible first digit X possible second digit X...............X possible tenth digit

9X10X10X10X10X10X10X10X10X10 = 9X10^{9} = 9.000.000.000

Let's find the amount of telephone numbers that "0" appears at most once (it means 0 will occur either once or will not occur):

If "0" appears once, the rest of the numbers should be 1.2.....9 (9 possible digits)

9X10X9X9X9X9X9X9X9X9 =10X9^{9} = 3.874.204.809

If "0" doesn't appear, the ten digits should be 1,2....9

9X9X9X9X9X9X9X9X9X9 = 9^{10} =3.486.784.401

Finally, find the probability

P=(favorable outcomes/total outcomes)

P=\frac{3.874.204.890 + 3.486.784.401}{9.000.000.000} = 0.82

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