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3 years ago

I really need help this is my second time......

Mathematics

1 answer:

KIM [24]3 years ago

7 0

First find the area of the triangle,
(8.4 x 24)/2 = 100.8
Then find the area of the parallelogram,
24 x 12 = 288

Then add both,
100.8+288 = 388.8 yd^2

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Determine which number is a solution of the inequality. j+8 ≤ 8; 0, 1, 2

Troyanec [42]

Answer:

The solution to the inequality is 0.

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2 years ago

Help, Please! I really need this done right Carlos is analyzing the results of an experiment on two groups of mice in which he c

Allushta [10]

Given:
difference in the mean weight gain is 0.60 grams
standard deviation of the difference in sample mean is 0.305

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3 years ago

What is the Y-Intercept and Slope of Y=10+1.75x?

Drupady [299]

Answer:

The slope is 1.75 and the y intercept is 10

Step-by-step explanation:

y = 10 +1.75x

y = 1.75x+10

This is in the form y = mx+b where m is the slope and b is the y intercept

The slope is 1.75 and the y intercept is 10

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2 years ago

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have

$i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079$

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3 years ago

Which of the following elevations are deeper than -200 feet? Select all that apply.

Serjik [45]

300 feet and 1300 feet

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3 years ago

Read 2 more answers