All categories

3 years ago

Prove that any number raised to the 0'th power equals 1

1 answer:

5 0

(a number)^to the 'A' power, divided by (the same number)^to the 'B' power =

   (the same number)^(A - B) power

If 'A' = 'B', then the numerator and the denominator are both

   (the same number)^to the same power,

and since (A - B = 0) , the quotient is   (the same number)^to the ( 0 ) power.

But a fraction with the same thing in the numerator and the denominator is '<em><u>1</u></em> '.

qed

You might be interested in

Answer please?!!!!!!!!!!!!!!!!!!!!!

Aleks [24]

Answer:

plz mark me as brsinliest..

3 0

2 years ago

NO SCAM. PLEASE SHOW WORK. WILL GIVE BRAINLY TO CORRECT ANSWER.

sergeinik [125]

Answer:

$140$

Step-by-step explanation:

A regular polygon is a shape with equal sides and angles. Because of this, we can write the following equation to set two sides equal to each other:

$3a+b+3=2a+2b+6$

Solving, we will get a in terms of b:

$3a=2a+b+3,\\a=b+3$

Now we can substitute a for (b+3) into our equation:

$5a-2b+1=2a+2b+6,\\5(b+3)-2b+1=2(b+3)+2b+6,\\3b+16=4b+12,\\-b=-4,\\b=\boxed{4}$

Therefore, the length of each side of this polygon is $5(4+3)-2(4)+1=28$ .

Since the perimeter of the polygon consists of all five sides, the perimeter is:

$p=28\cdot 5 =\boxed{140}$

6 0

2 years ago

Read 2 more answers

WILL GIVE BRAINLIEST FOR A CORRECT ANSWER:

guapka [62]

Answer:

Solution:

the boat's speed in still water: x

The speed with current: (x+3)

The speed against current: (x-3)

The equation is

3(x+3) = 4(x-3)

x = 21 mph

The distance = 3*(21+3)= 72 miles

I choose (A)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Every day your friend commutes to school on the subway at 9 AM. If the subway is on time, she will stop for a $3 coffee on the w

Shtirlitz [24]

Answer:

1.02% probability of spending 0 dollars on coffee over the course of a five day week

7.68% probability of spending 3 dollars on coffee over the course of a five day week

23.04% probability of spending 6 dollars on coffee over the course of a five day week

34.56% probability of spending 9 dollars on coffee over the course of a five day week

25.92% probability of spending 12 dollars on coffee over the course of a five day week

7.78% probability of spending 12 dollars on coffee over the course of a five day week

Step-by-step explanation:

For each day, there are only two possible outcomes. Either the subway is on time, or it is not. Each day, the probability of the train being on time is independent from other days. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

The probability that the subway is delayed is 40%. 100-40 = 60% of the train being on time, so $p = 0.6$

The week has 5 days, so $n = 5$

She spends 3 dollars on coffee each day the train is on time.

Probabability that she spends 0 dollars on coffee:

This is the probability of the train being late all 5 days, so it is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.6)^{0}.(0.4)^{5} = 0.0102$

1.02% probability of spending 0 dollars on coffee over the course of a five day week

Probabability that she spends 3 dollars on coffee:

This is the probability of the train being late for 4 days and on time for 1, so it is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.6)^{1}.(0.4)^{4} = 0.0768$

7.68% probability of spending 3 dollars on coffee over the course of a five day week

Probabability that she spends 6 dollars on coffee:

This is the probability of the train being late for 3 days and on time for 2, so it is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{5,2}.(0.6)^{2}.(0.4)^{3} = 0.2304$

23.04% probability of spending 6 dollars on coffee over the course of a five day week

Probabability that she spends 9 dollars on coffee:

This is the probability of the train being late for 2 days and on time for 3, so it is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{5,3}.(0.6)^{3}.(0.4)^{2} = 0.3456$

34.56% probability of spending 9 dollars on coffee over the course of a five day week

Probabability that she spends 12 dollars on coffee:

This is the probability of the train being late for 1 day and on time for 4, so it is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592$

25.92% probability of spending 12 dollars on coffee over the course of a five day week

Probabability that she spends 15 dollars on coffee:

Probability that the subway is on time all days of the week, so $P(X = 5)$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{5,5}.(0.6)^{5}.(0.4)^{0} = 0.0778$

7.78% probability of spending 12 dollars on coffee over the course of a five day week

8 0

3 years ago

1. Which of the following sets of numbers could represent the lengths of the sides of an acute triangle?

statuscvo [17]

Answer:

Step-by-step explanation:

That would be an isosceles triangle, therefore, acute. All angles measure 60, therefore being acute. I'm not 100% sure though.

7 0

3 years ago