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damaskus [11]
3 years ago
6

Solve the equation. 72 = 3f. F=?​

Mathematics
1 answer:
AysviL [449]3 years ago
8 0
F would be 8 because of 3 and 8
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. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir
mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

      P(U |D ) = 0.198

b

   P(O\ n \ B) = 0.188

c

  P(O | B) =   0.498

Step-by-step explanation:

The total number of deaths is mathematically represented as

      T   =  16 +  23 + \cdots  +  16

        T   =623

The total number of deaths in 1996 - 2000 is mathematically represented as

     T_a =  16 +  23+ \cdots + 30

      T_a = 235

The total number of deaths in 2001 - 2005 is mathematically represented as

     T_b =  17 +  16 + \cdots + 23

      T_b = 206

The total number of deaths in 2006 - 2010 is mathematically represented as

     T_c =  15 +  17 + \cdots + 16

      T_d = 182

Generally the the probability that it would occur under the tree given that the death was  after  2000 is mathematically represented as

     P(U |D ) = \frac{P(A \ n\  U )}{P(A)}

Here  P(A \ n\  U ) represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

         P(A \ n\  U )   = \frac{Z}{ T}

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

         Z =  35 +  42

=>       Z =  77

=>       P(A \ n\  U )   = \frac{77}{ 623}

=>      

Also

     P(A) is the probability of the death occurring after 2000  and this is mathematically represented as

        P(A) =  \frac{T_b  +  T_c}{ T}

=>      P(A) =  \frac{ 206+  182}{623}

=>  

So

         P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+  182}{623}}

=>      P(U |D ) = 0.198

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

      P(O | B) = \frac{T_z}{ T}

Here T_z is the total number of death outside / camping before 2001  and the value is  117  

So

            P(O \ n \ B) = \frac{117}{623}

=>          P(O\ n \ B) = 0.188

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

       P(O | B) =  \frac{ P( O \ n \ B)}{ P(B)}

Here P(B) is the probability that it was before 2001 , this is mathematically represented as  

          P(B ) =  \frac{T_a}{T}

=>       P(B ) =  \frac{235}{623}

So

          P(O | B) =  \frac{ \frac{117}{623}}{ \frac{235}{623}}

=>       P(O | B) =   0.498

5 0
3 years ago
Can you help me please ​
Readme [11.4K]

The area of the sector which is the white triangle adding the shaded region is 68.9/360*π*9.28^2=51.78005(rounding to 5th digit after decimal point for accuracy before we do final round for answer)

The area of the white triangle in the sector has area 1/2*9.28^2*sin(68.9)= 40.17223(rounding to 5 digits again for some accuracy.

Now we take out the white triangle from the sector.

51.78005-40.17223=11.60782

rounding to the nearest tenth we get 11.6 cm^2

Problem done!

Hope this helped and if you have any questions about my explanation just ask in the comment and I will answer.

5 0
3 years ago
15 divided by 22.8.
JulijaS [17]
.6578 this would be the answer
6 0
3 years ago
Tracy bought 6 bags of m&ms in each bag weighs 5/8 of a pound how many pounds of m&ms did tracy buy?​
kozerog [31]

Answer:

Exact Form:

\frac{15}{4}

Decimal Form:

3.75

Mixed Number Form:

3  \frac{3}{4}

Step-by-step explanation:

Multiply \frac{5}{8} by 6, and it equals 3 \frac{3}{4} pound of m&ms

Hope this helps :)

8 0
3 years ago
I’ll give you an extra 60 points please me within 5 minutes
azamat

Answer: (3p^2 + 1) . (p^3 +4)

Step-by-step explanation:

Area of a rectangle equals length multiplied by width. Given length as 3p^2 + 1 and width as p^3 + 4

Area = 3p^2 + 1) . (p^3 +4)

This is so as 4 is not a cube and cannot be factored.

I hope this helps.

7 0
3 years ago
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