The approximate age of a woman whose normal systolic pressure measures 125 mm Hg is 31
The function is given as:

When the normal systolic pressure is 125, it means that:

So, we have:

Subtract 125 from both sides of the equation


Rewrite the equation as:

Using a graphing calculator, we have:

But age cannot be negative.
So, we have:

Approximate

Hence, the age of the woman is 31
Read more about quadratic functions at:
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Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
Rise over run. as time increases the temperature rises. starting at 8am and -2°f.
At 12pm the temperature rose to 4°f.
that's a difference of 4 hours and 6 degrees. for every hour, it rose 1.5 degrees. the slope is 1.5/1