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dangina [55]
2 years ago
14

5. Let f be a continuous and differentiable function for all real numbers. The only critical points for f are located

Mathematics
1 answer:
ollegr [7]2 years ago
6 0
Ok so the answer is super simple, its A
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55x5<img src="https://tex.z-dn.net/?f=55x5%3D%5C%5C" id="TexFormula1" title="55x5=\\" alt="55x5=\\" align="absmiddle" class="lat
mash [69]

Answer:

55 times 5 is 275

Step-by-step explanation:

what's the other stuff

5 0
3 years ago
12. In the diagram below…
aniked [119]
It is number 3 why beacseu if u don’t have the length them u can’t do the equation
4 0
2 years ago
Write the integral that gives the length of the curve y = f (x) = ∫0 to 4.5x sin t dt on the interval ​[0,π​].
Troyanec [42]

Answer:

Arc length =\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx

Arc length =9.75053

Step-by-step explanation:

The arc length of the curve is given by \int_a^b \sqrt{1+[f'(x)]^2}\ dx

Here, f(x)=\int_0^{4.5x}sin(t) \ dt interval [0, \pi]

Now, f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( [-cos(t)]_0^{4.5x} \right )

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( -cos(4.5x)+1 \right )

f'(x)=4.5sin(4.5x)

Now, the arc length is \int_0^{\pi} \sqrt{1+[f'(x)]^2}\ dx

\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx

After solving, Arc length =9.75053

5 0
3 years ago
Someone please help me.
leva [86]

Answer:

All

Step-by-step explanation:

The answer is 1, 2, 3

I, II, III

5 0
3 years ago
What is 2/3 x 21 and 15 x 2/3 and witch is greater
ANTONII [103]
2/3 x 21 is correct because 21 is bigger than 15

6 0
3 years ago
Read 2 more answers
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