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3 years ago

8

Please help quickly I don’t understand

1 answer:

aksik [14]3 years ago

8 0

The answer is 22

Do you need an explanation?

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Write the complex numbers in standard form: 5/ 8-i

dedylja [7]

Answer:

a+bi

$\frac{8}{13} + \frac{i}{13}$

5 0

3 years ago

Value of x for 12(x-2)+3x=1/2(x+6)+2

Damm [24]

Answer:

The value of x = 2

Step-by-step explanation:

Given the equation

$12\left(x-2\right)+3x=\frac{1}{2}\left(x+6\right)+2$

Expand 12(x-2) = 12x - 24

Expand 1/2(x+6) = 1/2x + 3

so the equation becomes

$12x-24+3x=\frac{1}{2}x+3+2$

simplifying

$15x-24=\frac{1}{2}x+5$

$15x=\frac{1}{2}x+29$

multiplying both sides by 2

$30x = x + 58$

subtracting x from both sides

$30x - x = 58 - x$

$29x = 58$

divide both sides by 29

$\frac{29x}{29}=\frac{58}{29}$

simplifying

$x = 2$

Therefore, the value of x = 2

4 0

3 years ago

In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>

Lemur [1.5K]

In both cases,

$AB^2=AD^2$

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

$(4x+7)^2=(6x-3)^2$

$16x^2+56x+49=36x^2-36x+9$

$20x^2-92x-40=0$

$5x^2-23x-10=0$

$(5x+2)(x-5)=0\implies\boxed{x=5}$

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

$(4x^2-18x-10)^2=(x^2+x+4)^2$

$16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16$

$15x^4-146x^3+235x^2+352x+84=0$

$(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}$

(again, omit the solutions that would give a negative length for either AB or AD)

7 0

3 years ago

Zigmanuir [339]

X/2 >= -4
x >= -4 * 2
x >= -8

6 0

3 years ago

tigry1 [53]

This most definitely has to be a rhombus since it is a form of a square with 4 congruent sides where a rectangle only has 4 right angles.
To clarify, a trapezoid only has one pair of parallel sides if you were wondering.

8 0

3 years ago