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11111nata11111 [884]
3 years ago
10

I need the named chemical compounds

Physics
1 answer:
alex41 [277]3 years ago
6 0

Answer: To name chemical compounds, first determine whether the compound is ionic, polyatomic, or covalent. If it is ionic, list the metal element first and then add the nonmetal element with the suffix “-ide.” This should result in a name like "aluminum oxide."

Explanation:

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It would fall under Mathematics
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20 points, just need a basic understanding. You are on a mystery planet, what you know is that from a height of 10.0 meters, a d
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(since you asked for basic understanding only, I am not including actual calculations. Please let me know in the comments section if you wish to verify your solution(s))

For (b): Use the formula for distance (s) made during an accelerated motion:

s = \frac{1}{2}at^2+ v_0t+s_0= \frac{1}{2}at^2= \frac{1}{2}gt^2

with v_0 and s_0 being the initial velocity and distance, both 0 in this case, and with "a" denoting the acceleration, in this case  solely due to gravitational acceleration so: "g."

You are given the distance made, namely 10 m, and the duration t (0.88s) and so using the formula above you can solve for g.

For (c), to determine the final velocity at time 0.88s use the formula for the instantaneous velocity of an accelerated motion

(velocity at time t) = (acceleration) x (time)  

again, with acceleration due to gravity, i.e., a = g and with g as determined under (b).  

If my calculation is correct, this mystery planet could be the Jupiter.


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4 years ago
When does a nebula become a star?
pashok25 [27]
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Heat is always transferred through the movement of matter in the convection mode of heat transmission.

<h3>What is heat transfer ?</h3>

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  • Here we can say that heat is transfer when there is movement between two books and hence there is change in temperature.

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6 0
2 years ago
A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest fro
Oksi-84 [34.3K]

Answer:

the equation of motion is

x(t) =-\frac{1}{6} \cos4\sqrt{6} t

Explanation:

Given that,

The weight attached to the spring is 24pounds

Acceleration due to gravity is 32ft/s²

Assume x is the string length, 4inches

convert the length inches to to feet = 4/12 = 1/3feet

From Hookes law , we calculate the spring constant k

k = W / x

k = 24 / (1/3)

k = 24 / 0.33

k = 72lb/ft

If the mass is displace from its equilibrium position by amount x

the differential equation is

m\frac{d^2x}{dt^2} + kx=0\\\\\frac{3}{4 } \frac{d^2x}{dt^2}+72x=0\\

\frac{d^2x}{dt^2} +96x=0

Auxiliary equation is

m^2+96=0\\m=\sqrt{-96} \\m=\_ ^+4\sqrt{6}

Thus the solution is,

x(t) =  c_1cos4\sqrt{6t} +c_2sin\sqrt{6t}

x'(t) =-4\sqrt{6c_1} sin4\sqrt{6t} +c_24\sqrt{6} cos4\sqrt{6t}

The mass is release from rest

x'(0) = 0

-4\sqrt{6c_1 }  \sin4\sqrt{6} (0)+c_24\sqrt{6} \cos4\sqrt{6} (0)=0\\c_24\sqrt{6} =0\\\\c_2=0

Therefore

x(t) = c₁ cos4 √6t

x(0) = -2inches

c₁ cos4 √6(0) = 2/12feet

c₁= 1/6feet

There fore, the equation of motion is

x(t) =-\frac{1}{6} \cos4\sqrt{6} t

7 0
4 years ago
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