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Kipish [7]
3 years ago
8

What is the mass of 50 N object on earth

Physics
1 answer:
Aleksandr [31]3 years ago
6 0

The average gravity on Earth is:

g=9.81\frac{m}{s^2}

Since N represents Newtons and Newtons is a measurement of force we can use the following equation:

F=ma

Where F is force, m is mass, and a is acceleration.  In this case the acceleration is the gravity acting on the object.  Therefore, F=50N, a=g=9.81m/s^2 and m is to be determined. And so:

F=ma\\\\F=mg\\\\50N=m(9.81\frac{m}{s^2} )\\\\\frac{50N}{9.81\frac{m}{s^2} } =m(\frac{9.81\frac{m}{s^2} }{9.81\frac{m}{s^2} } )\\5.0968kg=m\\\\m=5.1kg

Therefore, the mass is approximately 5.1 kg.

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6 0
3 years ago
6. Decelerating a plane at a uniform rate of -8 m/s2, a pilot stops the plane in 484 m. How
uysha [10]

Answer: 88 m/s

Explanation:

If we are talking about an acceleration at a uniform rate, we are dealing with constant acceleration, hence we can use the following equation:

{V_{f}}^{2}={V_{o}}^{2}+2ad (1)

Where:

V_{f}=0 Is the final velocity of the plane (we know it is zero because we are told the pilot stops the plane at a specific distance)

V_{o} Is the initial velocity of the plane

a=-8m/s^{2} is the constant acceleration of the plane

d=484m is the distance at which the plane stops

Isolating  V_{o} from (1):

V_{o}=\sqrt{-2ad} (2)

V_{o}=\sqrt{-2(-8m/s^{2})(484m)} (3)

Finally:

V_{o}=88m/s This is the veocity the plane had before braking began

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An upward force act on a proton as it moves with a speed of 2.0 x 10^5 meters/seconds through a magnetic field of 8.5 x 10^2
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Force on a moving charge is given by formula

\vec F = q(\vec v \times \vec B)

here we know that this force will be maximum when velocity is perpendicular to magnetic field

\vec F = qvB

here we know that

v = 2.0 \times 10^5 m/s

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F = (1.6 \times 10^{-19})(2 \times 10^5)(8.5 \times 10^2)

F = 2.72 \times 10^{-11} N

7 0
4 years ago
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