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JulijaS [17]
4 years ago
11

20 points, just need a basic understanding. You are on a mystery planet, what you know is that from a height of 10.0 meters, a d

ropped ball takes 0.88 seconds to hit the ground.
a. List givens

b. Calculate g

c. Determine the final velocity of the ball before striking the ground.
Physics
1 answer:
ICE Princess25 [194]4 years ago
7 0

(since you asked for basic understanding only, I am not including actual calculations. Please let me know in the comments section if you wish to verify your solution(s))

For (b): Use the formula for distance (s) made during an accelerated motion:

s = \frac{1}{2}at^2+ v_0t+s_0= \frac{1}{2}at^2= \frac{1}{2}gt^2

with v_0 and s_0 being the initial velocity and distance, both 0 in this case, and with "a" denoting the acceleration, in this case  solely due to gravitational acceleration so: "g."

You are given the distance made, namely 10 m, and the duration t (0.88s) and so using the formula above you can solve for g.

For (c), to determine the final velocity at time 0.88s use the formula for the instantaneous velocity of an accelerated motion

(velocity at time t) = (acceleration) x (time)  

again, with acceleration due to gravity, i.e., a = g and with g as determined under (b).  

If my calculation is correct, this mystery planet could be the Jupiter.


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Since the two arrows are parallel to each other, then the mirror must be perpendicular to the two arrows. That is, the incident ray and the reflected ray must be perpendicular to the mirror.

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4 years ago
What work is done by a system on its environment when an ideal gas is maintained at a constant pressure of 200 newtons/meter2 du
Crank

<u>Answer:</u>

Work done done by a system on its environment is W=40 Joules

<u>Explanation:</u>

<u>Given:</u>

Ideal gas is maintained at a constant pressure P=200 \frac{N}{m^{2}}

Change in Volume d v= -0.2 m^{3}

<u>To find:</u>  

Work done by a system during an Isobaric Process

<u>Solution:</u>  

In a Isobaric Process, constant pressure is maintained, P=200 \frac{N}{m^{2}}

According to the formula,

work done  \bold{W=P \times d v}

Substitute the values of pressure and change in volume in the above formula,

=200 \times -0.2

=40 \text { Joules }

<u>Result:</u>  

Work done done by a system W= -40 Joules

8 0
3 years ago
Read 2 more answers
A 4.5 g coin sliding to the right at 23.8 cm/s makes an elastic head-on collision with a 13.5 g coin that is initially at rest.
Airida [17]

Answer:

a) v = 11.9\times 10^{-2}\,\frac{m}{s} \,(11.9\,\frac{cm}{s} ), b) \Delta K = 9.559\times 10^{-5}\,J

Explanation:

a) The final velocity of the 13.5 g coin is found by the Principle of Momentum Conservation:

(4.5\times 10^{-3}\,kg)\cdot (23.8\times 10^{-2}\,\frac{m}{s} )+(13.5\times 10^{-3}\,kg})\cdot (0\,\frac{m}{s} ) = (4.5\times 10^{-3}\,kg)\cdot (-11.9\times 10^{-2}\,\frac{m}{s} )+(13.5\times 10^{-3}\,kg})\cdot v

The final velocity is:

v = 11.9\times 10^{-2}\,\frac{m}{s} \,(11.9\,\frac{cm}{s} )

b) The change in the kinetic energy of the 13.5 g coin is:

\Delta K = \frac{1}{2}\cdot (13.5\times 10^{-3}\,kg)\cdot \left[(11.9\times 10^{-2}\,\frac{m}{s} )^{2}-(0\,\frac{m}{s} )^{2}\right]

\Delta K = 9.559\times 10^{-5}\,J

4 0
3 years ago
Read 2 more answers
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