Answer:
y=-2/3x+20/3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(4-6)/(4-1)
m=-2/3
y-y1=m(x-x1)
y-6=-2/3(x-1)
y=-2/3x+2/3+6
y=-2/3x+2/3+18/3
y=-2/3x+20/3
Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
The sound intensity of rustling leaves, y = 20 decibels
<u>Step-by-step explanation:</u>
y = 10logx
The sound intensity of rustling leaves is 100 times the reference intensity.
x = ratio of intensity of sound to reference to intensity
x = 100:1 or x = 100
y = 10 log(100) = 10 * 2 = 20 decibels
y = 20 decibels
I’ll help you out, but what are the numbers in between? Like does it go boy 0, .3, .6, .9, to 1? Or is there a different pattern
