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True [87]
3 years ago
9

Point M is the midpoint of segment AB. Find the X Coordinate of the midpoint M if A (5.1,4.6) and B (7.9,2.5). Round to the near

est tenth if needed.
Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0

Answer:

6.5

Step-by-step explanation:

  5.1+7.9=13

13 divided by 2

     = 6.5

     

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Jaffrey was offered a job at $950 per month with a $22 increase every month for the first year. How much money can he make in th
iogann1982 [59]

Answer:

Jaffrey will end up making $1214 in the first year

Step-by-step explanation:

950 + 12(22) = ?

first lets find out what 12 * 22 =?

12 * 22 = 264

now lets add 264 to 950

264 + 950 = 1214

5 0
3 years ago
Evaluate S5 for 400 + 200 + 100 + … and select the correct answer below.
Nadusha1986 [10]
The correct answer is B) 775 

Why 775? Because Assume the series continues.

400+200+100+50+25=775

I hope this helps. 

Have a great day. :)
5 0
3 years ago
Read 2 more answers
2x + (3)(x) + (3)(4)
S_A_V [24]

Answer:

if you were looking for the solution i think it is Solution

5 + 1 2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
At what point on the curve y = 19 2x is the tangent line perpendicular to the line 20x 4y = 1?
Gennadij [26K]

The points are; (7/2, -1/2).

<h3>What is the given point?</h3>

Now the tangent line is given as;20x 4y = 1. When we rewrite it in the slope intercept form, we have the equation as; y = 1 - 20x/4 or y = 1/4 - 5x.

Then to obtain the slope of the curve we have; y = 19 - 2x

dy/dx = 2

Using the relation;

m1m2 = -1

m2 = -1/2

Hence;

y = 1/4 - 5(-1/2)

y = 1/4 + 5/2

y = 7/2

Thus the points are; (7/2, -1/2)

Learn more about normal curve:brainly.com/question/10664419

#SPJ4

7 0
2 years ago
Find a vector 3 units long in the opposite direction from v = 〈3, 1,-4).
lutik1710 [3]

Unit vector along the direction v = <3,1,-4> is :

\hat{v} = \dfrac{3i + j  -4k}{\sqrt{3^2 + 1^2 + 4^2}}\\\\\hat{v} = \dfrac{3i + j -4k}{5.1}

So, unit vector opposing the \hat{v} is :

\hat{v'} = -\hat{v}\\\\\hat{v'} = -( \dfrac{3i + j -4k}{5.1})\\\\\hat{v'} = \dfrac{-3i - j +4k}{5.1}

so, vector of magnitude 3 units in opposite direction from v is :

\vec{V} = 3\hat{v'}\\\\\vec{V} = \dfrac{3}{5.1}( -3i -j+4k)

Hence, this is the required solution.

5 0
3 years ago
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