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Nesterboy [21]
3 years ago
7

the spring was compressed three times farther and then the block is released, the work done on the block by the spring as it acc

elerates the block is
Physics
1 answer:
frosja888 [35]3 years ago
8 0

Answer:

The work done on the block by the spring as it accelerates the block is 4kx².

Explanation:

Let initial distance is x.

It was compressed three times farther and then the block is released, new distance is 3x.

The work done in compressing the spring is given by :

W=\dfrac{1}{2}k(x_2^2-x_1^2)

W=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\W=\dfrac{1}{2}k((3x)^2-x^2)\\\\W=\dfrac{1}{2}k((9x^2-x^2)\\\\W=\dfrac{1}{2}k\times 8x^2\\\\W=4kx^2

So, the work done on the block by the spring as it accelerates the block is 4kx².

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