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Lerok [7]
3 years ago
14

Find the height of a baseball with a mass of 0.15 kg that has a GPE of 73.5 J. Help please?

Physics
2 answers:
LUCKY_DIMON [66]3 years ago
8 0
Hight is 50 b/c it is on the ledt side



Slav-nsk [51]3 years ago
4 0
Gravitational Potential Energy of an object, relative to the ground =

           (mass) x (acceleration of gravity) x (height above the ground)


               73.5 J  =  (0.15 kg)  x  (9.8 m/s²)  x  (height above the ground).

1 J = 1 kg · m² / s²

               73.5 kg·m²/s²  =  (0.15 kg) · (9.8 m/s²) · (height)

Divide each side by (0.15 kg): 

               (73.5 kg·m² / (0.15 kg·s²)      = (9.8 m/s²) · (height)

Divide each side by (9.8 m/s²):

               (73.5 kg·m²·s²) / (0.15 kg·s² · 9.8 m)  =  (height)

After doing all the arithmetic on the left side:

               (73.5) / (0.15 · 9.8) (m)   =   height

                       50                 (m)    =   height
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antiseptic1488 [7]

Answer:

Explanation:

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3 0
3 years ago
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The helicopter was deformed and destroyed in the __?___ collision.
MariettaO [177]

Answer:

The helicopter was deformed and destroyed in the inelastic collision.

Explanation:

  • When two object collide there exist two way of colliding: elastic collision and inelastic collision.
  • Two terms are considered during the collision: kinetic energy and momentum.
  • If both of these terms are conserved in any collision then there is no significant loss of property, this is called as elastic collision.
  • If only momentum is conserved but kinetic energy is converted into other forms then it is inelastic collision. In inelastic collision, the energy is lost in the form of vibration, sound etc. causing the damage to colliding object.
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5 0
3 years ago
An oscillator consists of a block of mass 0.628 kg connected to a spring. When set into oscillation with amplitude 27 cm, the os
oksian1 [2.3K]

Answer:

T=0.372 s, f=2.7 Hz, w=16.9 rad/s, k=179.2 N/m, v= 8.78 m/s, F= 48.4 N

Explanation:

a.)

Period: It is already given in the question "oscillator repeats its motion every 0.372 s".

So T=0.372 s

b)

frequency= f = 1/ T

f = 1/ 0.372

f=2.7 Hz

c).

Angular frequency= w= 2πf

w= 2*π*2.7

w=16.9 rad/s

d)

Spring Constant:

As w=\sqrt{k/m}

⇒w²= k/m

⇒k= m*w²

⇒k= 0.628 * 16.9² N/m

⇒k=179.2 N/m

e)

The mass will have maximum speed when it passes through the mean position.

At mean position

Maximum elastic potential energy = Maximum kinetic energy

1/2 k A² = 1/2 m v²    ( A is amplitude of oscillation)

⇒ v=\sqrt{k A^2/m}

⇒ v= \sqrt{179.2 * 0.27/ 0.628}\

⇒ v= 8.78 m/s

f)

Maximum force will be exerted on the block when it is at maximum distance.

F= k* A   ( A is amplitude of oscillation)

F= 179.2 * 0.27 N

F= 48.4 N

5 0
3 years ago
What happens to light when it strikes the inside surface of a smooth, curved mirror? It bounces in random directions. It bounces
kotykmax [81]
This is a concave mirror you're talking about, so all of the points are going to converge to a single focal point. Therefore the answer would be that it bounces back toward a single spot
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3 years ago
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