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noname [10]
2 years ago
10

A 2.35-m-long wire having a mass of 0.100 kg is fixed at both ends. The tension in the wire is maintained at 22.0 N.

Physics
1 answer:
ahrayia [7]2 years ago
8 0

Length of wire (L)=2.35m

Mass of wire (m)=0.100kg(m)=0.100kg

Tension in the wire (T)=0.042m

<h3>What is tension?</h3>

Any physical object that is in contact with another one can apply forces to that item. Depending on the sorts of objects in touch, we label these contact forces differently. We refer to the force as tension if a rope, string, chain, or cable is one of the things applying the force.

Ropes and cables can effectively convey a force over a long distance, making them valuable for exerting forces (e.g. the length of the rope). For instance, a team of Siberian Huskies can pull a sled by attaching ropes to them, allowing the dogs to move more freely than if they had to push against the sled's rear surface with their typical effort.

learn more about tension refer:

brainly.com/question/23560853

#SPJ4

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What is the energy in joules of a mole of photons associated with red light of wavelength 7.00 × 102 nm?
konstantin123 [22]
<span>The energy of a single photon is given by E = hc/lambda, where h is Planck's constant, c is the speed of light, and lambda is the wavelength. Plugging the values in gives E = 6.63E-34 x 3.00E8 / 700E-9 = 2.84E-19 Joules Now one mole of substance is equivalent to 6.02E23 particles, so one mole of these photons will be: 2.84E-19 x 6.02E23 = 1.71E5 Joules</span>
4 0
3 years ago
A student releases a marble from the top of a ramp. The marble increases
Fed [463]

Answer:

Vf = 69.56 cm/s

Explanation:

In order to find the final speed of the ramp, we will use the equations of motion. First we use second equation of motion to find out the acceleration of marble:

s = Vi t + (1/2)at²

where,

s = distance traveled = 160 cm

Vi = Initial Speed = 0 cm/s (since, marble starts from rest)

t = time interval = 4.6 s

a = acceleration = ?

Therefore,

160 cm = (0 cm/s)(4.6 s) + (1/2)(a)(4.6 s)²

a = (320 cm)/(4.6 s)²

a = 15.12 cm/s²

Now, we use first equation of motion:

Vf = Vi + at

Vf = 0 cm/s + (15.12 cm/s²)(4.6 s)

<u>Vf = 69.56 cm/s</u>

7 0
3 years ago
A. 24.89<br> B. 25.89<br> C. 17.74<br> D. 19.73
Veronika [31]

Answer: D

Explanation:

Just did it got an 100

5 0
2 years ago
A(n) ________ is a specialized bursa that wraps around a tendon to reduce friction.
Kisachek [45]

Tendon Sheath - is a specialized bursa that wraps around a tendon to reduce friction.

<h3>What is Tendon Sheath ?</h3>

Tendon Sheath is a thin layer of tissue, surrounds each tendon in our body. The tendon sheath can also be called synovial lining or fibrous sheath. Tendon sheaths help to protect tendons from abrasive damage as they move.

Connection between Bursa and Tendon Sheath : Bursae are small fluid-filled sacs that can lie under a tendon, cushioning the tendon and protecting it from the injury. Bursae also provides an extra cushioning to adjacent structures that otherwise might rub against each other, which will cause wear and tear ( example, between a bone and a ligament ) .

So, lastly we can say that Tendon Sheath is the specialized bursa that wraps around a tendon to reduce friction.

To know more about Tendon Sheath please click here : brainly.com/question/17087116

#SPJ4

8 0
1 year ago
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional
Nostrana [21]

Answer:

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Explanation:

i just got it right on edgenuity :)

6 0
3 years ago
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