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vodomira [7]
3 years ago
13

Please help me

Physics
1 answer:
melamori03 [73]3 years ago
7 0
<h2>Question:</h2>

An automobile is driving uphill. Which form of energy is not involved in this process?

<h2>Choosing:</h2>

electromagnetic

potential

kinetic

chemical

<h2>Answer:</h2>

<u>Electromagnetic</u><u> </u>

<h3><u>#READINGHELPSWITHLEARNING</u><u> </u></h3><h3><u>#CARRYONLEARNING</u><u> </u></h3><h3><u>#STUDYWELL</u><u> </u></h3>
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A parallel-plate capacitor has plates of area 0.40 m2 and plate separation of 0.20 mm. The capacitor is connected to a 9.0 V bat
mafiozo [28]

Answer:

a) E = 4.5*10⁴ V/m

b) C= 17.7 nF

c) Q = 159. 3 nC  

Explanation:

a)

  • By definition, the electric field is the electrostatic force per unit charge, and since the potential difference between plates is just the work done by the field, divided by the charge, assuming a uniform electric field, if V is the potential difference between plates, and d is the separation between plates, the electric field can be expressed as follows:

       E = \frac{V}{d} = \frac{9.0V}{2*10-4m} =4.5 * 10e4 V/m (1)

b)

  • For a parallel-plate capacitor, applying the definition of capacitance as the quotient between the charge on one of the plates and the potential difference between them, and assuming a uniform surface charge density σ, we get:

       Q = \sigma* A (2)

        From (1), we know that V = E*d, but at the same time, applying Gauss'

        Law at a closed surface half within the plate, half outside it , it can be

        showed than E= σ/ε₀, so finally we get:

       C = \frac{Q}{V} =\frac{\sigma*A}{E*d}  = \frac{\sigma*A}{\frac{\sigma}{\epsilon_{o} } d} =\frac{\epsilon_{0}*A}{d} = \frac{8.85e-12F/m*0.4m2}{2e-4m} = 17.7 nF (3)

c)    

  • From (3) we can solve for Q as follows:

       Q = C* V = 17.7 nF * 9.0 V = 159.3 nC  (4)

6 0
3 years ago
You push very hard on a heavy desk, trying to move it. You do work on the desk:
frozen [14]

Answer:

(C) Only if it starts moving

Explanation:

We know that work done is given by

W=F.d=Fdcos\Theta

So there are two case in which work done is zero

First case is that when force and displacement are perpendicular to each other

And other case is that when there is no displacement

So for work to be done there must have displacement, if there is no displacement then there is no work done

So option (c) will be the correct option

3 0
3 years ago
During an ,
nadya68 [22]

Answer:

1.5*10^9

Explanation:

distance =V x T

=3x10^8x5

=1.5*10^9

8 0
3 years ago
The ball in front of you is going to drop one meter. how long will it take to fall?
Pavlova-9 [17]

The ball will take 0.45 seconds to reach the ground

<h3>How will we solve this question?</h3>

We will use Newton’s laws of motion, so

H= (1/2)gt^2 taking height= 1m

1= (1/2) x 9.8 x t^2

t=\sqrt{10/49} = 0.45 seconds

<h3>What are the three laws of motion given by Newton?</h3>

The 3 laws of motion given by Newton are as follows:

1) Unless an unbalanced force acts upon it, an item at rest remains at rest, and an object in motion continues to move in a straight line at a constant pace.

2) An object's acceleration is influenced by its mass and the force being applied.

3) Whenever one thing applies force to another, the second object applies the opposing, equal force to the first.

To know more about Newton's laws of motion visit:

brainly.com/question/27915475

#SPJ4

7 0
2 years ago
vague terms are often used in advertising because they can have more than one meaning true or false??
Elan Coil [88]
True ! Examples: brighter, refreshing, easy, fine, firm, satisfying.
6 0
3 years ago
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