Answer:
We conclude that segment QR is the shortest.
Hence, option B is true.
Step-by-step explanation:
First, we need to determine the missing angle m∠R
Given the triangle Δ∠PQR
m∠P = 48°
m∠Q = 83°
m∠R = ?
We know the sum of angles of a triangle is 180°.
m∠P+m∠Q+m∠R = 180°
48°+83°+m∠R=180°
m∠R = 180° - 48° - 83°
m∠R = 49°
Thus, the value of m∠R = 49°
We know that the longest side in a triangle is opposite the largest angle, and the shortest side is opposite the smallest angle.
Here,
m∠P = 48° is the shortest angle.
As the side QR segment is opposite the smallest angle i.e. m∠P = 48°
Therefore, we conclude that segment QR is the shortest.
Hence, option B is true.
Answer:
We don't have sufficient evidence to support the claim
Step-by-step explanation:
Null hypothesis:
Alternate hypothesis:
The P-value is 0.3064
0.3064 probability of finding a sample proportion lower than the one found.
The p-value is higher than the significance level of 0.05, which means that there is no sufficient evidence to support the claim.
Answer:
I am pretty sur it is 3
Step-by-step explanation:
Answer: PEnis
Step-by-step explanation: pe + nis= penis
Answer:
φ ≈ 1.19029 radians (≈ 68.2°)
Step-by-step explanation:
There are simple formulas for A and φ in this conversion, but it can be instructive to see how they are derived.
We want to compare ...
y(t) = Asin(ωt +φ)
to
y(t) = Psin(ωt) +Qcos(ωt)
Using trig identities to expand the first equation, we have ...
y(t) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)
Matching coefficients with the second equation, we have ...
P = Acos(φ)
Q = Asin(φ)
The ratio of these eliminates A and gives a relation for φ:
Q/P = sin(φ)/cos(φ)
Q/P = tan(φ)
φ = arctan(Q/P) . . . . taking quadrant into account
__
We can also use our equations for P and Q to find A:
P² +Q² = (Acos(φ))² +(Asin(φ))² = A²(cos(φ)² +sin(φ)²) = A²
A = √(P² +Q²)
_____
Here, we want φ.
φ = arctan(Q/P) = arctan(5/2)
φ ≈ 1.19029 . . . radians
