Answer:
Step-by-step explanation:
Use the zero-interval test [test point (0, 0)] to verify them as false or true, and to determine whether we shade the shared opposite portions [a shared portion that does NOT contain the origin] or the shared portions that DO contain the origin:

![\displaystyle 0 < -3[0] - 2 → 0 ≮ -2](https://tex.z-dn.net/?f=%5Cdisplaystyle%200%20%3C%20-3%5B0%5D%20-%202%20%E2%86%92%200%20%E2%89%AE%20-2)
So, this system will be shaded in a shared opposite portion.
*NOTE; Both inequalities have an identical y-intercept of
so both inequalities must intersect the y-axis at
and since there are already lines labeled as <em>dashed</em><em> </em>and solid, we do not have to worry about it in this case.
** None of the other graphs match this, so the bottom right graph has to be it, considering it cut off.
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Answer: y = |x+4|
Explanation:
Imagine that the graph of y = |x| is carved in stone so it cannot move. What we can move though is the xy axis. If we move the xy axis 4 units to the right, then this gives the illusion the V shaped curve is moving 4 units to the left. It goes opposite whatever movement you do to the xy axis.
If we replaced x with x+4, then this moves the xy axis 4 units to the right.
Therefore, going from y = |x| to y = |x+4| will have the V shaped curve moving 4 units to the left.
Answer: spencer left after 14 days
Step-by-step explanation: