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s344n2d4d5 [400]
3 years ago
13

What is tally marks?​

Mathematics
2 answers:
balu736 [363]3 years ago
8 0

Answer:

tally mark also called hash marks and they are a unary numeral system

kiruha [24]3 years ago
3 0
Tally marks, also called hash marks, are a unary numeral system. They are a form of numeral used for counting. They are most useful in counting or tallying ongoing results, such as the score in a game or sport, as no intermediate results need to be erased or discarded. Every fifth mark is drawn across the previous 4 marks, so you can easily see groups of 5

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-9______ -7<br><br> A.&gt;<br> B.&lt;<br> C.=
Alla [95]

Answer:

B

Step-by-step explanation:

B, -9 < -7 it is correct ansewer

5 0
3 years ago
A sugar cube is inch on each edge. How much volume does it occupy?
Serhud [2]

Hello from MrBillDoesMath!

Answer:

1 cubic inch.

Discussion:

If each side of the sugar cube is 1, the volume, which is the product of the length, width, and height, equals

1 * 1 *1  =

1 cubic inch.


Thank you,

MrB

5 0
3 years ago
What is the first step in solving this equation? 2(3x - 4) = 3x + 1 a combine like terms b move x to the other side c distributi
laila [671]
You need to do the distributive property first so the answer is C
7 0
3 years ago
Simplify 4( 3+ 7y) + 6(2 - y) if y =2
UkoKoshka [18]

Answer:

68

Step-by-step explanation:

The expression is given as:

4( 3+ 7y) + 6(2 - y)

It is known that y is equal to 2. Therefore, substitute 2 in for y.

4(3+7(2))+6(2-2)

Now, solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

Solve inside of the parentheses first.

4(3+7(2))+6(2-2)

4(3+14)+6(0)

4(17)+6(0)

Multiply

68+0

Add

68

8 0
3 years ago
If the probability of selecting, without replacement, 2 red marbles from a bag containing only red and blue marbles is 3 55 and
Marat540 [252]

Answer:

Step-by-step explanation:

Let T = the TOTAL number of marbles in the bag.

We are told that 3 of those marbles are red

P(select a red marble first) = 3/T

Once we've removed the first red marble, there are T-1 marbles remaining and 2 of them are red

So, P(select a red marble second) = 2/(T-1)

Okay, now let's use probability rules to answer the question....

P(select 2 red marbles) = P(select a red marble first AND select a red marble second)

= P(select a red marble first) x P(select a red marble second)

= 3/T x 2/(T-1)

= 6/(T² - T)

We're told that P(select 2 red marbles) = 3/55

So, we can write: 6/(T² - T) = 3/55

Cross multiply to get: 3(T² - T) = (6)(55)

Divide both sides by 3 to get: T² - T = (2)(55)

Evaluate: T² - T = 110

Rearrange: T² - T - 110 = 0

Factor: (T - 11)(T + 10) = 0

So, EITHER T = 11 OR T = -10

Since T cannot be negative, it must be the case that T = 11

6 0
3 years ago
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