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Setler79 [48]
3 years ago
7

Help me plz 10 points

Mathematics
2 answers:
Kitty [74]3 years ago
8 0

Answer:

just arrange the numbers from least to greatest but if the number is in range between the numbers on the bottom they go on the same line

diamong [38]3 years ago
5 0
I’m sorry follow the instructions the other person put
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3/a times x -4 equals 20
jenyasd209 [6]

Answer:

a = -5/3

Step-by-step explanation:

3/a × -4 = 20

3a × -4/-4 = 20/-4

3a = -5

a = -5/3

Check:

3/(-5/3) × - 4 = 20

-5 × - 4 = 20

4 0
1 year ago
The solution for 6x-8=7x is x—8 show the steps you would go through to check. That answer
prisoha [69]
6x-8=7x
-6x -6x
-8=1x
-8=x
5 0
3 years ago
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If 3x = y - 5 and x = -4, then y = ? <br> A)-7 <br> B)3 <br> C)7 <br> D)17 <br> E)9
fredd [130]

Answer:

<h3>3×(-4) = y - 5</h3><h3>= ) -12 = y -5 </h3><h3>=) -12 +5 =y </h3><h3>=) -7 = y</h3>

<h2>y =-7</h2>

8 0
3 years ago
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If (-2, y) lies on the graph of y = 4x, then y =<br><br> -16<br> 1/16<br> 16
emmasim [6.3K]
Y = 4x
(-2,y).....x = -2

y = 4(-2)
y = -8
7 0
3 years ago
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The sea turtle habitat at the zoo is made by connecting two large aquariums. The first aquarium is 6\text { m}6 m6, space, m lon
iren [92.7K]

First aquarium dimensions:

Length = 6 m.

Width = 4 m and

Height = 2 meter.

Second aquarium dimensions:

Length = 8 m.

Width = 9 m and

Height = 3 meter.

We know formula for volume of a cuboidal box = Length*Width*Height.

Plugging values of length, width and height of first aquarium in formula of volume. We get

V1 = 6*4*2 = 48 m^3.

Plugging values of length, width and height of second aquarium in formula of volume. We get

V2 = 8*9*3 = 216 m^3.

In order to find the total cubic meters of space do the sea turtles have in their habitat, we need to add both volumes.

Therefore, Total voulme of both aquarium = V1 +V2 = 48+216 = 264 m^3.

Therefore, total 264 m^3 cubic meters of space the sea turtles have in their habitat.

8 0
3 years ago
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