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3 years ago

The cell phone company charges $42 plus .02 per text (t). Which algebraic expression represents the total charge per

Mathematics

1 answer:

evablogger [386]3 years ago

4 0

Answer:

the answer is b) 42 + .02t

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The difference of twice a number and 3

KiRa [710]

2n/3
the difference means divide 2 times(multiply)a number

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3 years ago

The table shows the number of cups of water required when cooking different amounts of rice.

Harman [31]

Answer-

The amount of water is the dependent value.

Solution-

Plotting the graph from the given data points, it comes out to be a straight line with positive slope. So, both the variables i.e amount of rice and amount of water are in a linear relationship. They are directly proportional to each other.

As the amount of rice increases, the water needed to cook the rice also increases. Plotting a graph taking amount of rice in abscissa and amount of water in ordinate, a straight line was obtained.

Here, amount of rice is the independent variable and amount of water is dependent variable as it depends on the amount of rice.

3 0

3 years ago

What is the quoteint of 3/4 and 5/6

Novosadov [1.4K]

Answer:

9/10

Step-by-step explanation:

Very simple, Keep It, Change It, Flip it

Do 3/4 X 6/5 and you should get your answer

5 0

2 years ago

Find the value of x in the triangle shown below.

almond37 [142]

Answer:

x=69.41860973

Step-by-step explanation:

We can use the law of sines

sin x sin 55

------------- = -----------

4 3.5

Using cross products

3.5 sin x = 4 sin 55

Divide each side by 3.5

sin x = 4/3.5 sin 55

Take the inverse sin of each side

x = sin ^-1 ( 4/3.5 sin 55)

x=69.41860973

7 0

3 years ago

Given that k is a positive integer. Find, in terms of k, an expression for Sn, which is the sum of the integers from 2k to 4k in

Elden [556K]

Answer:

$S_n=3k\cdot (2k+1)=6k^2 +3k$

Step-by-step explanation:

k is a positive integer.

Consider an arithmetic sequence:

$a_1=2k\\ \\a_n=4k\\ \\d=1$

First, find n:

$a_n=a_1+(n-1)\cdot d\\ \\4k=2k+(n-1)\cdot 1\\ \\2k=n-1\\ \\n=2k+1$

Now, find the sum of these 2k+1 terms:

$S_n=\dfrac{a_1+a_n}{2}\cdot n\\ \\S_n=\dfrac{2k+4k}{2}\cdot (2k+1)=\dfrac{6k}{2}\cdot (2k+1)=3k\cdot (2k+1)=6k^2 +3k$

7 0

3 years ago