#a
V={Vowels of English alphabets}
#b
C={cube numbers between 0 to 50}
#c
M={y:y is a multiple of 3 less than 20}
Answer:
x = 1.71
Step-by-step explanation:
![x^3-20=-15\\x^3=-15+20\\x^3=5\\\sqrt[3]{x^3} =\sqrt[3]{5} \\x=1.71](https://tex.z-dn.net/?f=x%5E3-20%3D-15%5C%5Cx%5E3%3D-15%2B20%5C%5Cx%5E3%3D5%5C%5C%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%5Csqrt%5B3%5D%7B5%7D%20%5C%5Cx%3D1.71)
First, we need to equalize the denominator. If the denominator multiplies by (x+1), so does the numerator. If the denominator multiplies by (x-1), so does the numerator.
Look into my attachment at the second row.
Second, because the first fraction and the second fraction have the same denominator, you can join them into one fraction.Look into my attachment at the third row.
Third, simplify the numerator.Look into my attachment at the fourth to the fifth row
Fourth, simplify the denominator.Look into my attachment at the sixth to the seventh row.
Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 90% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.645.
The sample size and the estimate are given by:

Hence, the bounds of the interval are given by:


The 90% confidence interval is given by: (0.6350, 0.6984).
More can be learned about the z-distribution at brainly.com/question/25890103
#SPJ1
1.)
Between year 0 and year 1, we went from $50 to $55.
$55/$50 = 1.1
The price increased by 10% from year 0 to year 1.
Between year 2 and year 1, we went from $55 to $60.50.
$60.50/$55 = 1.1
The price also increased by 10% from year 1 to year 2. If we investigate this for each year, we will see that the price increases consistently by 10% every year.
The sequence can be written as an = 50·(1.1)ⁿ
2.) To determine the price in year 6, we can use the sequence formula we established already.
a6 = 50·(1.1)⁶ = $88.58
The price of the tickets in year 6 will be $88.58.