6z½ write each expression in radical form

Make and test a conjecture about the given quantity.

larisa [96]

Answer:

18. The conjecture is: The product of two negative even integers is an even integer.

Testing: Let integers be -4 and -6. [Two negative even integers]

Then (-4) × (-6) = 24 [Even integer]

19. The conjecture is: Sum of two negative odd integers is a negative even integer.

Testing: Let the two negative odd integers be -3 and -7.

Then -3 + (-7) = -10 is a negative even integer

20. The conjecture is: Sum of two even integers and two odd integers is an even integer.

Testing: Let integers be 4, 12, 13, 17 (Two even integers and two odd integers)

Then 4 + 12 + 13 + 17 = 46 (Even integer)

21. The statement is: p------->q [If you ran 1 mile, then you ran 5280 feet]

Decide whether statement is true: So if p is True then q is also True.

Hence p------->q is True. So the given statement is True.

Step-by-step explanation:

18. The product of two negative even integers.

Let the integers be -2m and -2n, m and n are positive integers

Product in (-2m) × (-2n) = 4mn = 2(2mn)

= 2p, p = 2mn

The conjecture is: The product of two negative even integers is an even integer.

Testing: Let integers be -4 and -6. [Two negative even integers]

Then (-4) × (-6) = 24 [Even integer]

19. The sum of two negative odd integers.

Let the integers be -(2m + 1) and -(2n + 1), m and n are positive integers

Then -(2m + 1) + [-(2n + 1)] = -2m - 1 - 2n - 1

= -2m - 2n - 2

= -2(+m + 2 + 1)

= -2p, p = m + n + 1

The conjecture is: Sum of two negative odd integers is a negative even integer.

Testing: Let the two negative odd integers be -3 and -7.

Then -3 + (-7) = -10 is a negative even integer

20. The sum of two even integers and two odd integers.

Let the integers be 2m, 2n, 2p + 1, 2q + 1 (m, n, p, q are positive integers)

Then, 2m + 2n + 2p + 1 + 2q + 1 = 2(m + n + p + q + 1)

= 2r, r = m + n + p + q + 1

The conjecture is: Sum of two even integers and two odd integers is an even integer.

Testing: Let integers be 4, 12, 13, 17 (Two even integers and two odd integers)

Then 4 + 12 + 13 + 17 = 46 (Even integer)

21. Let p: You ran 1 mile

Let q: You 5280 feet

The statement is: p------->q [If you ran 1 mile, then you ran 5280 feet]

Since 1 mile = 5280 feet

So if p is True then q is also True.

Hence p------->q is True. So the given statement is True.

6 0

3 years ago

Solve this equation q - 17 = 18 Thanks!

Lisa [10]

Answer:

q =1

Step-by-step explanation:

q=17-18

.•. q=1

pls mark me as a hot boy

8 0

3 years ago

Read 2 more answers

Yoo can someone do this for me

o-na [289]

Answer:

Angle 5

Step-by-step explanation:

Adjacent angles share a common side and a common vertex.

6 0

3 years ago

Flaming BBQ Restaurant makes a dipping sauce with 9\text{ mL}9 mL9, space, m, L of hot sauce for every 666 ounces of barbecue sa

ahrayia [7]

Answer:

3 mL of hot sauce mixed with 2 ounces of barbecue sauce

45 mL of hot sauce mixed with 30 ounces of barbecue sauce

12 mL of hot sauce mixed with 8 ounces of barbecue sauce

Step-by-step explanation:

we know that

A restaurant makes a dipping sauce with

$\frac{9}{6}\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

Simplify

$1.5\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

Verify each case

case A) we have

6 mL of hot sauce mixed with 10 ounces of barbecue sauce

so

$\frac{6}{10}\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

simplify

$0.6\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

Compare

$0.6 \neq 1.5$

therefore

This mixture is not the same that as Flaming BBQ's dipping sauce

case B) we have

3 mL of hot sauce mixed with 2 ounces of barbecue sauce

so

$\frac{3}{2}\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

simplify

$1.5\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

Compare

$1.5 =1.5$

therefore

This mixture is the same that as Flaming BBQ's dipping sauce

case C) we have

45 mL of hot sauce mixed with 30 ounces of barbecue sauce

so

$\frac{45}{30}\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

simplify

$1.5\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

Compare

$1.5=1.5$

therefore

This mixture is the same that as Flaming BBQ's dipping sauce

case D) we have

24 mL of hot sauce mixed with 18 ounces of barbecue sauce

so

$\frac{24}{18}\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

simplify

$1.33\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

Compare

$1.33 \neq 1.5$

therefore

This mixture is not the same that as Flaming BBQ's dipping sauce

case E) we have

12 mL of hot sauce mixed with 8 ounces of barbecue sauce

so

$\frac{12}{8}\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

simplify

$1.5\ \frac{mL\ hot\ sauce}{oz\ barbecue\ sauce}$

Compare

$1.5=1.5$

therefore

This mixture is the same that as Flaming BBQ's dipping sauce

6 0

4 years ago

What number are listed in the stem and leaf plot above

Paul [167]

The numbers listed are:

3, 3 ,3 ,7 ,8 ,8 ,11 ,11 ,13 ,14 ,15 ,17, 18, 19, 21, 23, 23 ,25,27, 28, and 29.

3 0

3 years ago

6z½ write each expression in radical form ​

6z½ write each expression in radical form