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zimovet [89]
3 years ago
15

What is the period function of f(x)=1/2tan (2x+5)

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Compare your f(x)=1/2tan (2x+5) to

g(x)=a*tan (bx + c).


Note how b = 2.


The period of the given tangent function is pi/b, which here is pi/2, or 90 degrees. Multiplying x by 2 horizontallyl compresses the graph of tan x by a factor of 1/2.

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Pretty please HELP MEEEE A circular flower bed is 19 m in diameter and has a circular sidewalk around it that is 3 m wide. Find
finlep [7]
I think the answer is 9.42m squared.

If I got the right answer, I would appreciate Brainliest. I hope I helped.
6 0
3 years ago
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4/9 is it equivalent to 20/36
Tasya [4]
No because

36 / 9 = 4

20 / 4 = 5

So they are multiplied by different amounts so they aren’t equivalent
5 0
3 years ago
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A right triangle has legs that measure 7 cm and 6 cm. What is the length of the hypotenuse in meters?
dalvyx [7]
<h2>Greetings!</h2>

Answer:

\sqrt{85}  or 9.22

Step-by-step explanation:

You need to remember the following equation:

a^{2} + b^{2} = c^{2}

Where a and b is the lengths of the two sides and c is the hypotenuse.

So simply plug these values into this:

6^{2} + 7^{2} = h^{2}

36 + 49 = h^2

36 + 49 = 85

So the hypotenuse is the square root of 85:

\sqrt{85}  = 9.22


<h2>Hope this helps!</h2>
7 0
3 years ago
Match the mean median mode and range for the data set below 16 9 20 10 12 6 8 15
blsea [12.9K]

Answer:

12 is mean     11 is median     range is 14

Step-by-step explanation:

For the Mean

Add all the numbers up

16 + 9 + 20 + 10 =55

12 + 6 + 8 + 15 = 41

55 + 41 = 96

There are 8 numbers so we divide by 8

96/8 = 12

Range is Smallest number minus biggest so 20 - 6 = 14

6 0
3 years ago
Read 2 more answers
A) how many ways are there to choose 10 players to take the field?
Kruka [31]

A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.

B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

10! 3!

9!1! 1!2! 10! 3!

8!2! 2!1! 10! 3!

7!3! 3!0!

= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =

= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

<span>possible choices.</span><span> 
</span>

  


5 0
3 years ago
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