The teacher will use 3 rolls only to have perfect measurements.
1 yard = 3 feet
4 large bulletin boards are there each needing 9 yards of border.
That means 4 large bulletin boards in total need
9×4 yards of border
= 36 yards of border
= 108 feet of border
Also, there is a small bulletin board that only needs 12 feet border
Hence, in total there is a need for
108 + 12 = 120 feet border.
The border is sold in 40-foot rolls.
Hence, there is a need for 120/40 rolls
i.e. 3 rolls
Hence, the teacher will use 3 rolls only.
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I would say the object will float because the density of water is 999.99kg/m which is slightly less than 1g but still more than the object.
Answer: $768.50
Step-by-step explanation:
If $725 was the price before sales tax, $768.50 would be the total amount after the 6% sales tax increase.
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Solution of 8 x 4 - 4 divided by 2 +1 is 9.33
<h3><u>Solution:</u></h3>
Given that,
8 x 4 - 4 divided by 2 +1
We have to compute the above equation
Let us write the given sentence mathematically:

Let us BODMAS rule to solve the above expression
According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right.
So let us first perform multiplication of 8 and 4 in numerator

Now we can perform addition of 2 and 1 in denominator

Now we can perform subtraction of 4 from 32 in numerator

Now perform division of 28 by 3

Thus solution of 8 x 4 - 4 divided by 2 +1 is 9.33
Answer:
The fraction of the area of ACIG represented by the shaped region is 7/18
Step-by-step explanation:
see the attached figure to better understand the problem
step 1
In the square ABED find the length side of the square
we know that
AB=BE=ED=AD
The area of s square is

where b is the length side of the square
we have

substitute


therefore

step 2
Find the area of ACIG
The area of rectangle ACIG is equal to

substitute the given values

step 3
Find the area of shaded rectangle DEHG
The area of rectangle DEHG is equal to

we have 

substitute
step 4
Find the area of shaded rectangle BCFE
The area of rectangle BCFE is equal to

we have


substitute

step 5
sum the shaded areas

step 6
Divide the area of of the shaded region by the area of ACIG

Simplify
Divide by 5 both numerator and denominator

therefore
The fraction of the area of ACIG represented by the shaped region is 7/18