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VikaD [51]
2 years ago
6

What is the slope of the line that passes through the points (4, -9)(4,−9) and (8, -3) ?(8,−3)? Write your answer in simplest fo

rm.
Mathematics
2 answers:
faltersainse [42]2 years ago
6 0

Answer:

\frac{3}{2}

Step-by-step explanation:

I am assuming that you mean (4,−9) and (8, -3).

m=\frac{rise}{run}=\frac{-3+9}{8-4}=\frac{6}{4}=\boxed{\frac{3}{2}}

Hope this helps.

sammy [17]2 years ago
3 0

Answer:gyftftft

Step-by-step explanation: vtcvcr

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A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say <em>E </em>occurring is:

P (E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let <em>X</em> = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, <em>n</em> = 20.

Number of defective electric toothbrushes is, <em>x</em> = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

{20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

{3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

                                                            =\frac{3}{190}\\

                                                            =0.01579\\\approx0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

8 0
3 years ago
Tony started his math project at 1{:}57\text { p.m.}1:57 p.m.1, colon, 57, space, p, point, m, point and finished the project 80
prisoha [69]

Answer:

43 minutes

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
What is the answer to number 8.
Viktor [21]

Its 20. |-2|+4-(-2)×(7). This simplifies to 2+4+(2×7)

4 0
3 years ago
find three consecutive even integers so that the twice the sum of the second and third is twelve less than six times the first
zysi [14]

n, n + 2, n + 4 - three consecutive even integers

the twice the sum of the second and third: 2[(n + 2) + (n + 4)]

twelve less than six times the first: 6n - 12

The equation:

2[(n + 2) + (n + 4)] = 6n - 12

2(n + 2 + n + 4) = 6n - 12

2(2n + 6) = 6n - 12       <em>use distributive property</em>

(2)(2n) + (2)(6) = 6n - 12

4n + 12 = 6n - 12       <em>subtract 12 from both sides</em>

4n = 6n - 24       <em>subtract 6n from both sides</em>

-2n = -24        <em>divide both sides by (-2)</em>

n = 12

n + 2 = 12 + 2 = 14

n + 4 = 12 + 4 = 16

<h3>Answer: 12, 14, 16</h3>
4 0
3 years ago
Please help me with this one. I need help right away.
lana66690 [7]

b(1 -2) i just too the test

6 0
3 years ago
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