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Setler [38]
3 years ago
13

One minute after it is released, a gas-filled balloon has risen 100 feet. In each succeeding minute, the balloon rises only 50%

as far as it rose in the previous minute. How far will the balloon rise in 5 minutes?
Mathematics
1 answer:
goldfiish [28.3K]3 years ago
8 0
The amount that it rises each minute forms a geometric sequence...

a(n)=ar^(n-1), and we know that a=100 ft and r=1/2 so

a(n)=100(1/2)^(n-1)

And the sum of a geometric sequence is:

s(n)=a(1-r^n)/(1-r)

s(n)=100(1-0.5^n)/(1-0.5)

s(n)=200(1-0.5^n)

So we can call these sums the height function

h(t)=200(1-0.5^t)

So after 5 minutes...

h(5)=200(1-0.5^5)

h(5)=193.75 ft
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A door of a lecture hall is in a parabolic shape. The door is 56 inches across at the bottom of the door and parallel to the flo
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Answer:

The parabolic shape of the door is represented by y - 32 = -\frac{2}{49}\cdot x^{2}. (See attachment included below). Head must 15.652 inches away from the edge of the door.

Step-by-step explanation:

A parabola is represented by the following mathematical expression:

y - k = C \cdot (x-h)^{2}

Where:

h - Horizontal component of the vertix, measured in inches.

k - Vertical component of the vertix, measured in inches.

C - Parabola constant, dimensionless. (Where vertix is an absolute maximum when C < 0 or an absolute minimum when C > 0)

For the design of the door, the parabola must have an absolute maximum and x-intercepts must exist. The following information is required after considering symmetry:

V (x,y) = (0, 32) (Vertix)

A (x, y) = (-28, 0) (x-Intercept)

B (x,y) = (28. 0) (x-Intercept)

The following equation are constructed from the definition of a parabola:

0-32 = C \cdot (28 - 0)^{2}

-32 = 784\cdot C

C = -\frac{2}{49}

The parabolic shape of the door is represented by y - 32 = -\frac{2}{49}\cdot x^{2}. Now, the representation of the equation is included below as attachment.

At x = 0 inches and y = 22 inches, the distance from the edge of the door that head must observed to avoid being hit is:

y -32 = -\frac{2}{49} \cdot x^{2}

x^{2} = -\frac{49}{2}\cdot (y-32)

x = \sqrt{-\frac{49}{2}\cdot (y-32) }

If y = 22 inches, then x is:

x = \sqrt{-\frac{49}{2}\cdot (22-32)}

x = \pm 7\sqrt{5}\,in

x \approx \pm 15.652\,in

Head must 15.652 inches away from the edge of the door.

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3 years ago
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