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Rudik [331]
3 years ago
6

Write the polynomial in standard form. Identify the degree and leading coefficient of the polynomial. Then classify the polynomi

al by the number of terms.
6c^2+ 2c^4 - c

Mathematics
1 answer:
Musya8 [376]3 years ago
3 0

Answer:

Standard form: 2c^4 + 6c^2 - c

Degree: 4th

Leading coefficient: 2

Classification: Trinomial

Step-by-step explanation:

In standard form, you have to put the term with the highest exponent first.

With finding the degree, you just look at the highest exponent and that's the degree. 4 is the highest exponent, so it is to the 4th degree.

The leading coefficient is the number attached to the highest exponent. 4 is the highest and the number attached to it is 2.

Classification goes by how many terms there are. Since there are 3, it's trinomial. Tri as in three.

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You need to see what you need to convert and how you need to convert it, do you need to divide to find out how many it goes in? Questions like that.
7 0
3 years ago
N+4-9 - 5n when simplifying
natita [175]

Answer:

-4n - 5

Step-by-step explanation:

4 - 9

= -5

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Combine like terms

= -4n

-4n - 5

7 0
3 years ago
A recipe uses 1/3 cup of brown sugar to make 18 cookies. How many cups of brown sugar are needed to make 45 cookies?
Alenkinab [10]

Answer:

5/6 cups of sugar

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
5n – 2n<br> I need help asap
blondinia [14]
Combining those like terms would end as 3n.

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7 0
3 years ago
marsha waide borrows 5,000 and agrees to pay it back in 2 years . if the simple interst rate is 13% ,find the total amount she p
Dmitry_Shevchenko [17]

Answer:

You want to calculate the interest on $5000 at 13% interest per year after 2 year(s).

The formula we'll use for this is the simple interest formula.

Where:

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t is the time involved, 2....year(s) time periods.

So, t is 2....year time periods.

To find the simple interest, we multiply 5000 × 0.13 × 2 to get that:

The interest is: $1300.00

Usually now, the interest is added onto the principal to figure some new amount after 2 year(s),

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3 years ago
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