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gavmur [86]
3 years ago
9

Please answer it for me

Mathematics
2 answers:
kupik [55]3 years ago
7 0
You would have to take 6336 steps because 63360 inches is one mile and that divided by 10 is 6336 
zhannawk [14.2K]3 years ago
3 0
6336 steps is what you have to take
You might be interested in
Im having trouble with my homework can u tell me what is x=3y
viktelen [127]
That's an equation that describes a linear and proportional relationship between 'x' and 'y'. The graph of that equation is a straight line through the origin whose slope is. 1/3 .
4 0
3 years ago
Read 2 more answers
Nick made his histogram showing the number of sport caps each of his friends own.
pickupchik [31]

Answer:

A. 7

Step-by-step explanation:

2 or 3 caps = 13

6 or 7 caps = 6

13 - 6 = 7

- hope this helps! -

3 0
2 years ago
Question12....................................
tatyana61 [14]

Answer:

u = ± 4

Step-by-step explanation:

Given

u² = 16 ( take the square root of both sides )

u = ± \sqrt{16} = ± 4

u = - 4, u = 4

5 0
3 years ago
D’Andra has a dentist appointment in 5 weeks. There are 7 days in a week. How many days are in 5 weeks?
Lisa [10]

Answer:

A. 35

Step-by-step explanation:

Each week has 7 days, and we have 5 weeks.

Week 1 has 7 days.

Week 2 has 7 days.

Week 3 has 7 days.

Week 4 has 7 days.

Week 5 has 7 days.

We can add all these together to get the total number of days: 7 + 7 + 7 + 7 + 7 = 7 * 5 = 35.

Thus, the answer is A.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Work out the area of abcd.<br><br> please ensure you give workings out too.
ipn [44]

Answer:

\displaystyle A_{\text{Total}}\approx45.0861\approx45.1

Step-by-step explanation:

We can use the trigonometric formula for the area of a triangle:

\displaystyle A=\frac{1}{2}ab\sin(C)

Where a and b are the side lengths, and C is the angle <em>between</em> the two side lengths.

As demonstrated by the line, ABCD is the sum of the areas of two triangles: a right triangle ABD and a scalene triangle CDB.

We will determine the area of each triangle individually and then sum their values.

Right Triangle ABD:

We can use the above area formula if we know the angle between two sides.

Looking at our triangle, we know that ∠ADB is 55 DB is 10.

So, if we can find AD, we can apply the formula.

Notice that AD is the adjacent side to ∠ADB. Also, DB is the hypotenuse.

Since this is a right triangle, we can utilize the trig ratios.

In this case, we will use cosine. Remember that cosine is the ratio of the adjacent side to the hypotenuse.

Therefore:

\displaystyle \cos(55)=\frac{AD}{10}

Solve for AD:

AD=10\cos(55)

Now, we can use the formula. We have:

\displaystyle A=\frac{1}{2}ab\sin(C)

Substituting AD for a, 10 for b, and 55 for C, we get:

\displaystyle A=\frac{1}{2}(10\cos(55))(10)\sin(55)

Simplify. Therefore, the area of the right triangle is:

A=50\cos(55)\sin(55)

We will not evaluate this, as we do not want inaccuracies in our final answer.

Scalene Triangle CDB:

We will use the same tactic as above.

We see that if we can determine CD, we can use our area formula.

First, we can determine ∠C. Since the interior angles sum to 180 in a triangle, this means that:

\begin{aligned}m \angle C+44+38&=180 \\m\angle C+82&=180 \\ m\angle C&=98\end{aligned}

Notice that we know the angle opposite to CD.

And, ∠C is opposite to BD, which measures 10.

Therefore, we can use the Law of Sines to determine CD:

\displaystyle \frac{\sin(A)}{a}=\frac{\sin(B)}{b}

Where A and B are the angles opposite to its respective sides.

So, we can substitute 98 for A, 10 for a, 38 for B, and CD for b. Therefore:

\displaystyle \frac{\sin(98)}{10}=\frac{\sin(38)}{CD}

Solve for CD. Cross-multiply:

CD\sin(98)=10\sin(38)

Divide both sides by sin(98). Hence:

\displaystyle CD=\frac{10\sin(38)}{\sin(98)}

Therefore, we can now use our area formula:

\displaystyle A=\frac{1}{2}ab\sin(C)

We will substitute 10 for a, CD for b, and 44 for C. Hence:

\displaystyle A=\frac{1}{2}(10)(\frac{10\sin(38)}{\sin(98)})\sin(44)

Simplify. So, the area of the scalene triangle is:

\displaystyle A=\frac{50\sin(38)\sin(44)}{\sin(98)}

Therefore, our total area will be given by:

\displaystyle A_{\text{Total}}=50\cos(55)\sin(55)+\frac{50\sin(38)\sin(44)}{\sin(98)}

Approximate. Use a calculator. Thus:

\displaystyle A_{\text{Total}}\approx45.0861\approx45.1

8 0
2 years ago
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