Which polynomial is equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x)?
<h3><u><em>
Answer:</em></u></h3>
The polynomial equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x) is
<h3><u><em>Solution:</em></u></h3>
Given that two polynomials are: and
We have to find the result when is subtracted from
In basic arithmetic operations,
when "a" is subtracted from "b" , the result is b - a
Similarly,
When is subtracted from , the result is:
Let us solve the above expression
<em><u>There are two simple rules to remember: </u></em>
- When you multiply a negative number by a positive number then the product is always negative.
- When you multiply two negative numbers or two positive numbers then the product is always positive.
So the above expression becomes:
Removing the brackets we get,
Combining the like terms,
Thus the resulting polynomial is found
Answer:
d (w) = 0.1w² – w+ 5
Step-by-step explanation:
d(w) = c(w) - a(w)
= -0.3w²+2w+13 -(-0.4w²+3w+8)
= -0.3w²+0.4w²+2w-3w+13-8
= 0.1w²-w+5
we are given
we can see that
numerator is
and denominator is
We always put coefficient of numerator inside box
we can see that coefficient of numerators are 3 , -4 and 9
and in the left side , we put value of x after putting denominator =0
so, left side will be 2
so, option-D..................Answer
The slope-intercept form of the equation of a straight line is y=mx+b, where m is the slope and b is the y-coordinate of the y-intercept.
If the given slope is -1/2, then this equation becomes y = (-1/2)x + b.
You do not say that b=1.
But if we let b=1, then the equation becomes y = (-1/2)x + 1.