Answer:
The answer is c
Step-by-step explanation:
The middle line is in the same spot
Answer:
Step-by-step explanation:
n=12.4+23.79-5.27
n=30.92
Answer:
<u>t = t₀ - 3n</u>
Step-by-step explanation:
Let t be the temperature and t₀ be the initial temperature of the day
Let n be the number of hours after the initial temperature ( t₀) was registered
Let -3 be the constant of change of temperature ( In 4 hours it went down 12 degrees)
Now, let's write down the expression that shows the temperature change each hour, this way:
t = t₀ - 3n
After 2 hours
t = t₀ - 3 * 2 = t₀ - 6
After 5 hours
t = t₀ - 3 * 5 = t₀ - 15
After 3 hours and 30 minutes
t = t₀ - 3 * 3.5 = t₀ - 10.5
Answer:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the z-score that has a p-value of
.
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.
This means that 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).