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Vinvika [58]
3 years ago
5

Area of right angle triangle is 54 cm2. if one of its leg is 12 cm fine the perimeter

Mathematics
1 answer:
Molodets [167]3 years ago
8 0
The perimeter of the right angled triangle should be 36cm, hope this helps:)
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What is the value of y?
mrs_skeptik [129]
Ok so you would start by getting rid of the fraction. You should know the steps for that by now but here this is what it would look like
3y/4+10=2y/4 Simplify
3y/4+10=1y/2
10=-1y 
I really simplified the last part but this is what it looks like:  \frac{2y}{4}- \frac{3y}{4} = -1y
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8 0
3 years ago
Read 2 more answers
Add and Subtract Rational Expressions with a Common Denominator
Sladkaya [172]

Answer:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}

Operating on the numerators:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}

Removing parentheses:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}

Simplifying:

\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}

The expression cannot be further simplified.

7 0
2 years ago
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GaryK [48]
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5 0
3 years ago
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vovangra [49]
The answer to that would be 5 !!!!
4 0
3 years ago
90oriX9 un rezultat va rog
bogdanovich [222]
The answer is 333.423 hope this helps u

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