Exponential growth and decay functions are written in standard form as
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Remark.
The easiest way to do this question is to graph it. Start with that.
The red line is y = (1/3)^x
The blue line is y = 5*(1/3)^x
Comment
The red line's y intercept is (0,1)
The blue line's y intercept is (0,5)
Why
If the x value is 0 then (1/3)^0 = 1
y = (1/3)^0 = 1 * 1 = 1 and for the blue graph
y = 5*(1/3)^0 = 5*1 = 5
In other words, in this set of equations, the 5 makes the y intercept 5 times larger than the 1 in front of y = (1/3)^x
If you have choices, could you please list them? I may be giving you the right answer but not in the form required.
The easiest way to do this question is to graph it. Start with that.
The red line is y = (1/3)^x
The blue line is y = 5*(1/3)^x
Comment
The red line's y intercept is (0,1)
The blue line's y intercept is (0,5)
Why
If the x value is 0 then (1/3)^0 = 1
y = (1/3)^0 = 1 * 1 = 1 and for the blue graph
y = 5*(1/3)^0 = 5*1 = 5
In other words, in this set of equations, the 5 makes the y intercept 5 times larger than the 1 in front of y = (1/3)^x
If you have choices, could you please list them? I may be giving you the right answer but not in the form required.