−20≤59(F−32)≤−15 please i need help<br><br> v+8 <3v+8 <3 or −8v<−40−8v<−40<br><br> 6

Express the mixed number 6 3/8 as a improper fraction? please show work.

Mkey [24]

6 3/8

Multiply the whole number with the denominator

6*8= 48. Add 3 ( numerator) with 48.

48+3= 51

51/8

Answer: 51/8

6 0

4 years ago

Logan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data

eduard

Answer:

we need the data to answer the question

3 0

4 years ago

Twelve students tried out for the cheerleading squad. Three students were selected. What is the ratio of students selected to th

dmitriy555 [2]

Answer:

1:4 I'm not sure though

4 0

3 years ago

Read 2 more answers

Find sec 2Theta in exact value

forsale [732]

Answer:

$sec(2\theta)=-\frac{5}{4}$

Step-by-step explanation:

we know that

step 1

Find $cos(\theta)$

we know that

$tan^2(\theta)+1=sec^2(\theta)$

we have

$tan(\theta)=3$

substitute

$3^2+1=sec^2(\theta)$

$sec^2(\theta)=10$

$sec(\theta)=\pm\sqrt{10}$

Remember that

Angle theta lie in Quadrant I

so

$sec(\theta)$ is positive

$sec(\theta)=\sqrt{10}$

Remember that

$sec(\theta)=\frac{1}{cos(\theta)}$

therefore

$cos(\theta)=\frac{1}{\sqrt{10}}$

step 2

Find $sin(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

$sin(\theta)=tan(\theta)cos(\theta)$

we have

$cos(\theta)=\frac{1}{\sqrt{10}}$

$tan(\theta)=3$

substitute

$sin(\theta)=(3)(\frac{1}{\sqrt{10}})$

$sin(\theta)=\frac{3}{\sqrt{10}}$

step 3

Find $cos(2\theta)$

we know that

$cos(2\theta)=2cos^2(\theta)-1$

we have

$cos(\theta)=\frac{1}{\sqrt{10}}$

substitute

$cos(2\theta)=2(\frac{1}{\sqrt{10}})^2-1$

$cos(2\theta)=\frac{1}{5}-1$

$cos(2\theta)=-\frac{4}{5}$

Remember that

$sec(2\theta)=\frac{1}{cos(2\theta)}$

therefore

$sec(2\theta)=-\frac{5}{4}$

8 0

3 years ago

Max ran 5 miles on Thursday. One mile is equal to 5,280 feet. Which proportion can be used to determine how many feet, x, Max ra

Scorpion4ik [409]

Answer:

1 mi/5280 ft = 5 mi/x ft

Step-by-step explanation:

1 mi = 5280 ft

This is the first fraction:

1 mi/5280 ft

The second fraction:

5 mi/x ft

If the problem asked specifically for the value of variable x, you would multiply 5 miles by 5280 feet to find it.

The problem only asks for the set up of the proportion though so:

1 mi/5280 ft = 5 mi/x ft

5 0

3 years ago

−20≤59(F−32)≤−15 please i need help v+8 <3v+8 <3 or −8v<−40−8v<−40 6