M<1 = 90 degrees. Since line B is perpendicular to line c, angle 5 and angle 6 are both 90 degrees (they bisect each other). Since angle 5 is 90 degrees, and corresponds to angle 1, angle 1 must also be 90 degrees.
Let's begin by listing out the information given to us:
We start out by observing that Triangles MKR & ACD are similar or proportional
We will solve for the missing side by using the similar triangle theorem. This is shown below:~
Answer:
Step-by-step explanation:
divide by 2 and square it
y+axSQUARED +bx+ c ----->(b/2)squared +d
2 ) add and subtract d to the equation
y = (axSQUARED +bx +d ) + c -d
factor the first part of the equation to match the vertex form and simplify
y= a(x-h)SQUARED + c- d
Y = a ( x - h SQUARED + k
<span>(2x^2 y^4)3
= 2^3 x^6 y^12
= 8x^6y^12
hope it helps</span>